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Salsk061 [2.6K]
2 years ago
9

A forest ranger in a 140-foot observation tower sees a fire moving in a direct path toward the windmill by the lake. The angle o

f depression to the fire is 3°, and the angle of depression to the windmill is 8°. To the nearest foot, how close is the fire to the windmill?
Mathematics
1 answer:
Hoochie [10]2 years ago
3 0
To get how close the windmill is to the fire we proceed as follows:
distance from watch tower to the fire will be:
tan θ= opposite/adjacent
opposite=140 ft
adjacent=x
θ=3°
hence
tan 3=140/x
x=140/tan 3
x=2,671.36 ft

the distance from watch tower to windmill will be:
tan θ=opposite/ adjacent
θ=8°
opposite=140 ft
adjacent=y
thus
tan 8=140/y
y=140/tan8
y=999.15 ft
the distance between fire and wind mill will be:
2,671.36-999.15
=1675.21~1675 ft (to the nearest ft)

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Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x + 1)? Check all that apply.
steposvetlana [31]
4(2 - x) > -2x - 3(4x + 1)
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x > -1.1

Therefore, x = 0 and x = 10 zre solutions to the inequality.
4 0
2 years ago
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If a piece of rope cost 20 cents per 2 feet, how many feet can you buy for 30 dollars?
katrin2010 [14]

Answer: 300\ feet

Step-by-step explanation:

Let be "x" the lenght in feet  of rope that you can buy with 30 dollars.

According to the information provided in the exercise, you can buy a piece of rope of 2 feet with 20 cents.

Remember that 20\ cents=0.2\ dollars

Knowing this, you can write the following proportion:

\frac{0.2}{2}=\frac{30}{x}

FInally, solving for "x", you get this result:

\frac{0.2}{2}=\frac{30}{x}\\\\x(\frac{0.2}{2})=30\\\\x=(30)(\frac{2}{0.20})\\\\x=300

6 0
2 years ago
If nothing is known about the shape of the distribution of a quantitative variable, what percentage of data fall within 2 standa
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Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases. (Assume that centra
Triss [41]

Answer:

Step-by-step explanation:

a) this involves 2 tails

The critical value is determined from the t distribution table.

α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 10

The critical value is 2.228

b) α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 20

The critical value is 2.086

c) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 20

The critical value is 2.845

d) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 60

The critical value is 2.660

e) 1 - α = 1 - 0.01 = 0.99

Looking at 0.99 with df 10

The critical value is 2.764

f) 1 - α = 1 - 0.025 = 0.975

Looking at 0.975 with df 5

The critical value is 2.571

6 0
2 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the
MissTica

A) The speed of the pedestrian BC is 5 km/h

    The speed of the pedestrian CD is 0 km/h

    The speed of the pedestrian DE is 5 km/h

B) He arrived E since the stop after 6 hours

C) The formula for section BC is d(t) = 40 - 5t

    The formula for section CD is d(t) = 20

    The formula for section DE is d(t) = 50 - 5t

Step-by-step explanation:

A)

In the time-distance graph the speed is the rate of change of distance

and that mean speed = Δd/Δt ⇒ (slope of the line)

In line BC:

1. Δd = 40 - 20 = 20 km

2. Δt = 4 - 0 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed of the pedestrian BC is 5 km/h

In line CD:

1. Δd = 20 - 20 = 0 km

2. Δt = 6 - 4 = 2 hours

3. The speed = 0 ÷ 2 = 0 km/h

The speed of the pedestrian CD is 0 km/h

In line DE:

1. Δd = 20 - 0 = 20 km

2. Δt = 10 - 6 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed of the pedestrian DE is 5 km/h

B)

∵ He stop at t = 4 hours

∵ He arrived at point E at t = 10 hours

∵ 10 - 4 = 6 hours

He arrived E since the stop after 6 hours

C)

The speeds are represented by lines

The form of the equation of a line is f(x) = mx + c, where m represents

the slope of the line and c is the y-intercept (y when x = 0)

1. f(x) is d(t)

2. m is the speed

3. x is t

4. You can find c by substitute d and t by any point on the line

Line BC

Line BC has negative slope because d decreases when t increases

∵ m = -5 and c = 40

∴ d(t) = 40 - 5t

The formula for section BC is d(t) = 40 - 5t

Line CD

Line CD is a horizontal line (equation any horizontal line is y = c)

∴ m = 0 and c = 20

∴ d(t) = 20

The formula for section CD is d(t) = 20

Line DE

Line DE has negative slope because d decreases when t increases

∵ m = -5

∴ d(t) = -5t + c

To find c substitute the coordinates of point D in the equation

∵ The coordinates of point D are (6 , 20)

∴ 20 = -5(6) + c

∴ 20 = -30 + c

Add 30 to both sides

∴ c = 50

∴ d(t) = 50 - 5t

The formula for section DE is d(t) = 50 - 5t

Learn more:

You can learn more about the distance, speed, and time in

brainly.com/question/5102020

#LearnwithBrainly

3 0
2 years ago
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