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2 years ago

7

Marcie built a scale model of the tallest building in town with an antenna on top. The model stands 6 2/3 centimeters tall. The

main building is 3/4 of the height of the building including the antenna. How tall is the antenna in the model? Pls help this is due today and i am really stressed out.

2 answers:

snow_tiger [21]2 years ago

8 0

The answer is gonna be 1/2

marysya [2.9K]2 years ago

7 0

The answer is 1/2...........

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The number of pages that Carolyn wrote in her journal each day from Monday to Friday is shown below: 9, 8, 12, 6, 10. What is th

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Answer:

She wrote 9 pages per day on average

Step-by-step explanation:

The number of pages that Carolyn wrote in her journal each day from Monday to Friday is shown below:

Monday = 9

Tuesday =8

Wednesday = 12

Thursday = 6

Friday = 10

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean =\frac{9+8+12+6+10}{5}$

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A salesman normally makes a sale (closes) on % of his presentations. Assuming the presentations are independent, find the pro

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Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

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So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

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$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

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Answer:

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Replace y with 0 and solve for x.

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