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4vir4ik [10]
1 year ago
12

Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11. negative 33 square root of

9 negative 11 square root of 9 negative 9 square root of 11 negative 9 square root of 33
Mathematics
1 answer:
Alla [95]1 year ago
6 0
As long as your indexes are the same (which they are; they are all square roots) and you radicands are the same (which they are; they are all 11), then you can add or subtract.  The rules for adding and subtracting radicals are more picky than multiplying or dividing.  Just like adding fractions or combining like terms.  Since all the square roots are the same we only have to worry about the numbers outside.  In fact, it may help to factor out the sqrt 11: (5-12-2) \sqrt{11}.  The numbers subtract to give you -9.  Therefore, the simplification is -9 \sqrt{11}
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Please help me!!!!!!!!!!
bezimeni [28]
9.2 x 13.8 = 126.96, now usually to get the area of a triangle we would half this but because we have two of the same triangle we would then have to double it again so they cancel each other out. We then do 6.9 x 9.2 which equals 63.48 and again we have two of the same triangle so no need to half it. So we add the two totals of 126.96 and 63.48 together to get 190.44.
4 0
1 year ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
Determine the input value for which the statement f(x) = g(x) is true. From the graph, the input value is approximately_______ .
Julli [10]

In this question , we have a graph given, and we have to find the x coordinate of the intersection point .

From the graph , the input value is approximately 3.3 .

In the graph,

f(x) =3

And for g(x), we need the slope and y intercept .

Slope is the ratio of rise and run .

Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .

So the equation of g(x) is

g(x) = \frac{3}{2}x -2

We need to do

f(x)= g(x)

Substituting the values of the two functions, we will get

3 = \frac{3}{2}x -2

Adding 2 to both sides

5 = \frac{3}{2}x

Cross multiplication

10 =3x
\\
x = \frac{10}{3}

x = 3.3

So the input value is 3.3 approx


6 0
1 year ago
Read 2 more answers
An elephant can run one over four mile in 36 seconds. Which of the following correctly shows this rate as miles per hour?
Vesnalui [34]
It would be thirty six seconds over one-fourth mile= 144 miles per hour
7 0
2 years ago
Read 2 more answers
119.31 is 82% of what number
madam [21]
To solve
82% of x = 119.31
rewrite
x = 119.31/0.82
solve
x <span>≈ 145.5</span>

Hope this helps :)
5 0
1 year ago
Read 2 more answers
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