Answer:
The coordinates of the mid-point of JL are (-5 , 2)
Step-by-step explanation:
If point (x , y) is the mid-point of a segment whose end-points are 
and 
, then 
and 
∵ JL is a segment
∵ The coordinates of J are (-6 , 1)
∴ 
= -6 and 
= 1
∵ The coordinates of L are (-4 , 3)
∴ 
= -4 and 
= 3
Lets use the rule above to find the mid-point of JL
∵ 
∴ x = -5
∴ The x-coordinate of the mid-point is -5
∵ 
∴ y = 2
∴ The y-coordinate of the mid-point is 2
∴ The coordinates of the mid-point of JL are (-5 , 2)
Answer:
7
Step-by-step explanation:
An equilateral triangle has a semiperimeter of 6 meters.
Heron’s formula: Area = StartRoot s (s minus a) (s minus b) (s minus c) EndRoot
An equilateral triangle has a semiperimeter of 6 meters. What is the area of the triangle? Round to the nearest square meter.
2 square meters
7 square meters
20 square meters
78 square meters
Answer: ₱40,909.1
Step-by-step explanation:
Given data:
Rate for first year = 4%
Rate for next two years = 6%
Rate for the next 3 years = 7.5%
Interest paid back after 5years = ₱ 15,750
Solution:
How much did she borrow.
= let the sum borrowed be P
= P * 4 / 100
= 4P/100
= 1P/25.
For the next two years
= P* 6 * 2/100
= 12P/100
= 3P/25
For the next 3years
= P* 7.5*3/100
= 22.5P/100
= 9P/40.
1P/25 + 3P/25 + 9P/40 = 15750
77P/200 = 15750
P = 15750 * 200 / 77
P = 315,0000/77
P = ₱40,909.1
The amount borrowed is ₱40,909.1
We have to find the" ratio of the area of sector ABC to the area of sector DBE".
Now,
the general formula for the area of sector is
Area of sector= 1/2 r²θ
where r is the radius and θ is the central angle in radian.
180°= π rad
1° = π/180 rad
For sector ABC, area= 1/2 (2r)²(β°)
= 1/2 *4r²*(π/180 β)
= 2r²(π/180 β)
For sector DBE, area= 1/2 (r)²(3β°)
= 1/2 *r²*3(π/180 β)
= 3/2 r²(π/180 β)
Now ratio,
Area of sector ABC/Area of sector DBE =
= 4/3
