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Flura [38]
2 years ago
6

-4/5, -1/2, 0.25, -0.2 least to greatest

Mathematics
1 answer:
galina1969 [7]2 years ago
3 0

Answer:

<em>-4/5,-1/2,-0.2,0.25</em>

Step-by-step explanation:

To order these, it would be best to convert them into decimals.

-4/5 is equal to -0.8

-1/2 is equal to -0.5

-0.8 is the least, because the further left on a number line, the less the number is.

-0.5 is next and then -0.2

Finally, 0.2 is the greatest

<em>-4/5,-1/2,-0.2,0.25</em>

<u>Hope this helps :-)</u>

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Answer:

The measure of Arc EH is 123°.

Step-by-step explanation:

Consider the diagram below.

It is provided that ∠EDH ≅ ∠EDG.

This implies that: ∠EDH = ∠EDG

The arc measure is same as the measure of the central angle.

That is:

arc FE = ∠EDF = 57°

arc FG = ∠FDG = 66°

Compute the measure of angle ∠EDH as follows:

arc EH = ∠EDH

           =∠EDG

           = ∠EDF + ∠FDG

           = 57° + 66°

           = 123°

Thus, the measure of Arc EH is 123°.

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2 years ago
a homeowner plans to hang wallpaper on one wall of a bedroom that is 10 feet long. if a strip of wallpaper is 20 inches wide and
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Six neighbors share 4 pies equally how much of a pie does each neighbor get
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Answer:

-5/6

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Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

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Finally,

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P(at least 1 win) = 1 - 0.3513

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2 years ago
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