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Varvara68 [4.7K]
2 years ago
14

Find a12 of the sequence 1/4,7/12,11/12,5/4,

Mathematics
1 answer:
Ludmilka [50]2 years ago
8 0

Answer:

Your ans is. a12 = 47/12

Step-by-step explanation:

First, you need to find if the series has a common ratio or a common difference between each term. Based from observation, there is a common difference of 1/3 so the series is an arithmetic series.

The solution for this problem goes like this

an=a1+(n-1)d

a12=1/n+(12-1)(1/3)

a12=47/12

Hope it helped you.. Please mark BRAINLIEST

Tysm

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shepuryov [24]
<span>angle measures in order from greatest to least.
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6 0
2 years ago
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In which set do all of the values make the inequality 2x - 1 &lt; 10 true?
igomit [66]

2x - 1 < 10\Leftrightarrow 2x < 11\Leftrightarrow x <  \frac{11}{2}

8 0
2 years ago
If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal
Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that 2x^2+y^2=17

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

4x+2yy'=0

2x+yy'=0

yy'=-2x

y'=-\frac{2x}{y}

Again differentiate w.r.t.x

Then , we get

2+(y')^2+yy''=0 (u\cdot v)'=u'v+v'u)

2+(y')^2+yy''=0

Using value of y'

yy''=-2-(-\frac{2x}{y})^2

y''=-\frac{2+(-\frac{2x}{y})^2}{y}

Substitute x=2 and y=3

Then, we get y''=-\frac{2+(\frac{4}{3})^2}{3}

y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}

Hence,y''=-1.26

6 0
2 years ago
Jim is building a rectangular deck and wants the length to be 1 ft greater than the width. what will be the dimensions of the de
Travka [436]
Let x = width
x+1 is then the length

2x+2(x+1)=66
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3 0
1 year ago
A function f(x) has x intercepts of -3 and -5. What is the constant term in the function?
Anon25 [30]

Answer:

The constant term in the function is 5

Step-by-step explanation:

we have

f(x)=x^{2}+8x+b

where

b is the y-intercept or the constant term of the function

Remember that

The x-intercept is the value of x when the value of the function is equal to zero

so

For x=-3 ----> f(x)=0

For x=-5 ----> f(x)=0

substitute any of the intercepts in the function

For x=-3

0=(-3)^{2}+8(-3)+b

0=9-24+b

0=-15+b

b=15

f(x)=x^{2}+8x+15

Verify with the other intercept

For x=-5

0=(-5)^{2}+8(-5)+15

0=25-40+15

0=0 ---> is true

therefore

The constant term in the function is 5

3 0
2 years ago
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