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Lera25 [3.4K]
1 year ago
12

If a set xy-axes has 20 grid units in each direction and the greatest value of the data to be placed on the horizontal axis is 1

32,what would be an appropriate and convenient scale to use for this axis?Explain.
Mathematics
1 answer:
Alborosie1 year ago
4 0
Use 7 scale point.
132/20 = 6.6
to its better to use more than 6.6 scale. to make it easier use 7, so to avoid decimals

 
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The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the
gladu [14]

Answer:

  • <u><em>The height of the missing rectangle is 0.15</em></u>

Explanation:

The image attached has the mentioned <em>histogram</em>.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

<u>1. Sum of the known relative frequencies</u>:

  • 0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85

<u>2. Missing frequency</u>:

  • 1 - 0.85 = 0.15

<u>3. Conclusion</u>:

  • The height of the missing rectangle is 0.15

4 0
1 year ago
Steve puts only dimes and quarters into his piggy bank. Right now he has five more dimes than quarters there, and they make exac
Serhud [2]
To get $74 in change using only Quarters and dimes would be 210 Quarters and 215 dimes which 210 quarters adds up too $52.50 and 215 dimes would add up too $21.50 add those together and you get $74 dollars exactly
7 0
2 years ago
4(5x−3)+5x+5 = 118<br><br> solve for x
EleoNora [17]

Answer:

x=1+2/15

Step-by-step explanation:

4(5x-3)=5x+5=118

We move all terms to the left:

4(5x-3)-(5x+5)=0

We multiply parentheses

20x-(5x+5)-12=0

We get rid of parentheses

20x-5x-5-12=0

We add all the numbers together, and all the variables

15x-17=0

We move all terms containing x to the left, all other terms to the right

15x=17

x=17/15

x=1+2/15

   

   

8 0
1 year ago
Evaluate these quantities.<br> a.−17 mod 2<br> b.144 mod 7<br> c.−101 mod 13<br> d.199 mod 19
Eduardwww [97]
Modular arithmetic is used to find the remainder when dividing the first number by the second number you can divide the term then multiply the  (or use the mod function of a graphing calculator with the first term first in the ordered pair and the second in the second term.

-17/2 = 8.5   2*.5 =1
a. 1
-144/7 = -20 5/7 . 4/7 *7 = 4
b. 4
-101/13 =
c. 3
199/19=
d.9

6 0
2 years ago
Salmon often jump waterfalls to reach their breeding grounds. One salmon starts 2.00m from a waterfall that is 0.55m tall and ju
Law Incorporation [45]

Answer: 6.2 m/s

Explanation:

1) This is a projectile motion (parabolic)

2) Velocity:

i) initial velocity = V₀

ii) Horizontal component:

V₀x = V₀ cos α

The horizontal velocity is constant, so Vx = V₀x

ii) Vertical component:

V₀y = V₀ sin α

The vertical component is linear with acceleration = g ≈ 9.8 m/s²

Vy = V₀y - gt = V₀ sin α - gt

3) Displacement equations

i) Horizontal displacment:

x = V₀ cosα t

ii) Vertical displacement:

y = V₀ sin α t - g t² / 2

y ≈ V₀ sin α t - 4.9 t²

4) Solution

i) x = V₀ cosα t = V₀ cos(32°) t = 2.00 m ← salmon starts 2.00m from a waterfall

⇒ V₀ = 2 / [cos(32°) t ]

ii) y = V₀ sin α t - 4.9 t² = V₀ sin(32°) t - 4.9 t²

iii) Replace V₀ with 2 / [cos(32°) t ]

y = sin(32°) × 2 / [cos(32°) t ] × t - 4.9t² = 2 tan(32°) - 4.9t²

iv) Use jump's height (y = 0.55m) and solve

⇒ 0.55 = 2 tan(32°) - 4.9t²

t² = [2 tan(32°) - 0.55 ] / 4.9 = 0.143 s²

⇒ t = √ (0.143s²) = 0.38 s

v) Use V₀ = 2 / [cos(32°) t ] to find V₀

V₀ = 2 / [cos(32°) (0.38) ] = 6.2 m/s

8 0
1 year ago
Read 2 more answers
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