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uysha [10]
2 years ago
8

Which is the graph of 2x – 4y > 6? On a coordinate plane, a dashed straight line with a positive slope goes through (negative

2, negative 2) and (1, 0). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (negative 3, negative 3) and (3, 0). Everything to the left of the line is shaded. On a coordinate plane, a dashed straight line with a positive slope goes through (negative 2, negative 2) and (1, 0). Everything to the left of the line is shaded. On a coordinate plane, a dashed straight line with positive slope goes through (negative 3, negative 3) and (3, 0). Everything to the right of the line is shaded.

Mathematics
3 answers:
Zina [86]2 years ago
8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

2x-4y > 6

solve for y

-4y >-2x+6

Divide by -4 both sides

Remember

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

y

The solution of the inequality is the shaded area below the dashed line y=0.5x-1.5

The slope of the dashed line is positive m=0.5

The y-intercept of the dashed line is (0,-1.5)

The x-intercept of the dashed line is (3,0)

therefore

The graph in the attached figure

Y_Kistochka [10]2 years ago
4 0

Answer:

its actually y < -3/2x+1

Step-by-step explanation:

i got it right by guessing lol

Guest1 year ago
0 0

it´s D on edge 2021

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The first-, second-, and third-year enrollment values for a technical school are shown in the table below.
VARVARA [1.3K]

Answer:

The solution to f(x) = t(x) is x = 2010

Option 3 is true.

Step-by-step explanation:

The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.

Year (x)      First Year f(x)      Second Year s(x)       Third Year t(x)

 2009              785                        756                           756

 2010               740                        785                           740

 2011                690                        710                            781

 2012               732                        732                            710

 2013                781                        755                            800

Now we will check each option.

Option 1: The solution to f(x) = s(x) is x = 2,009

In year 2009, f(x)=s(x)

But 785≠756

Thus, False

Option 2: The solution to f(x) = s(x) is x = 785

x represents year, but 785 it no year

Thus, False

Option 3: The solution to f(x) = t(x) is x = 2010

In year 2010, f(x)=t(x)=740

But 740=740

Thus, True

Option 4: The solution to f(x) = t(x) is x =740

x represents year, but 740 it no year

Thus, False

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2 years ago
If the probability is 0.54 that Stock A will increase in value during the next month and the probability is 0.68 that Stock B wi
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P(A) =0.54

P(B)= 0.68

P'(A)= 1-0.54 = 0.46

P'(B)= 1- 0.68 = 0.32

The probability of neither of both event will occur:

= P'(A)×P'(B)

=0.46 × 0.32

=0.1472

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Robin and evelyn are playing a target game. the object of the game is to get an object as close to the center as possible. each
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According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg
Sati [7]

Answer:

a) Mean blood pressure for people in China.

b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d) 8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

f) 157.44mmHg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is two standard deviations from the mean or more, it is considered unusual.

In this question:

\mu = 128, \sigma = 23

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

Z = \frac{X - \mu}{\sigma}

Z = \frac{135 - 128}{23}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

Z = \frac{X - \mu}{\sigma}

Z = \frac{141 - 128}{23}

Z = 0.565

Z = 0.565 has a pvalue of 0.7140

71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg.

This is the pvalue of Z when X = 125 subtracted by the pvalue of Z when X = 120. So

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 128}{23}

Z = -0.13

Z = -0.13 has a pvalue of 0.4483

X = 120

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 128}{23}

Z = -0.35

Z = -0.35 has a pvalue of 0.3632

0.4483 - 0.3632 = 0.0851

8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?

From b), when X = 135, Z = 0.3

Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg.

f.) What blood pressure do 90% of all people in China have less than?

This is the 90th percentile, which is X when Z has a pvalue of 0.28. So X when Z = 1.28. Then

X = 120

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 128}{23}

X - 128 = 1.28*23

X = 157.44

So

157.44mmHg

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