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kifflom [539]
2 years ago
5

Lin knows that there are 4 quarts in a gallon. She wants to convert 6 quarts to a gallon, but cannot decide if she should multip

ly 6 by 4 or divide 6 by 4 to find her answer. What should she do? Explain or show your reasoning.
Mathematics
1 answer:
defon2 years ago
5 0

Given:

There are 4 quarts in a gallon.

She wants to convert 6 quarts to a gallon.

To find:

Whether she should multiply 6 by 4 or divide 6 by 4 to find her answer.

Solution:

We have,

4\text{ quarts}=1\text{ gallon}

1\text{ quarts}=\dfrac{1}{4}\text{ gallon}

6\text{ quarts}=\dfrac{6}{4}\text{ gallon}

Here, 6 quarts is equal to \dfrac{6}{4} gallon. It means we need to multiply 6 by 4 in 4\text{ quarts}=1\text{ gallon} to find the answer.

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2x+5y=-6 , wht is the x intercept, what is the y intercept
Arlecino [84]
These are the <span>xx</span> and <span>yy</span> intercepts of the equation <span><span>2x−5y=6</span><span>2x-5y=6</span></span>.x-intercept: <span><span>(3,0)</span><span>(3,0)</span></span>y-intercept: <span>(0,−<span>65</span><span>)

</span></span>
7 0
2 years ago
On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne
Oksanka [162]

Answer:

The perimeter is (8\sqrt{2}+2\sqrt{10})\ units

Step-by-step explanation:

we know that

A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal

so

In this problem

PS=QR ----> equation A

SR=PQ ----> equation B

The perimeter of parallelogram PQRS is

P=PQ+QR+SR+PS ----> equation C

substitute equation A and equation B in equation C

P=2SR+2QR

we have

QR=\sqrt{10}\ units

SR=4\sqrt{2}\ units

substitute in the formula of perimeter

P=2(4\sqrt{2})+2(\sqrt{10})

P=(8\sqrt{2}+2\sqrt{10})\ units

7 0
2 years ago
Read 2 more answers
Which of the following slopes show that the set of points C(1, 1), D(3, -4), E(5, 8) are not collinear?
MArishka [77]
C is the answer you want

8 0
2 years ago
Read 2 more answers
Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa
aleksley [76]

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

5 0
1 year ago
Read 2 more answers
The diagram shows the cross section of a cylindrical pipe with water lying in the bottom.
disa [49]
Hey 

So my brother posted this on Yahoo 
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm. 

<span>What you do now is the following: </span>

<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>

<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>

<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>

<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>



<span>b) </span>

<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>

Hoped it Helped
5 0
1 year ago
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