Answer:
Step-by-step explanation:
xy = 2y + xy = 0
Hence, 2y + xy = 0 ---------(1)
Differentiating equation (1) n times by Leibnitz theorem, gives:
2y(n) + xy(n) + ny(n - 1) = 0
Let x = 0: 2y(n) + ny(n - 1) = 0
2y(n) = -ny(n - 1)
∴ y(n) = -ny(n - 1)/2 for n ≥ 1
For n = 1: y = 0
For n = 2: y(1) = -y
For n = 3: -3y(2)/2
For n = 4: -2y(3)
h(x) = -2x2 + 12x - 3?
The axis of symmetry is :
x = 3
Hope this helps.
Welcome to Brainly!,
Davinia.
The right answer is C
Let me to explain. From the graph we know that the vertex of this parabola is
. This is a<em> maximum y-value.</em> We also know that the parabola <em>opens downward, </em>so the leading coefficient is negative. Given that the function is even and the leading coefficient is negative, it follows that the graph falls to the left and right. In a mathematical language this is:
<em> </em>
Answer:
Anna's walk as a vector representation is
and refer attachment.
Step-by-step explanation:
Let the origin be the point 1 from where Ann start walking.
Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,
Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)
Ann walk as a vector representation is 
Thus, Anna's walk as a vector representation is 