Answer:
a. P(X ≤ 5) = 0.999
b. P(X > λ+λ) = P(X > 2) = 0.080
Step-by-step explanation:
We model this randome variable with a Poisson distribution, with parameter λ=1.
We have to calculate, using this distribution, P(X ≤ 5).
The probability of k pipeline failures can be calculated with the following equation:
Then, we can calculate P(X ≤ 5) as:
The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:
.04b is 2% of 2b because .04 multiplied by 100 is 4 then you divide by 2 which gets you 2.
.04/2=x/100
cross multiply and divide
it is 98% smaller than 2b.
.2b is 10% of 2b because .2 multiplied by 100 is 20 then you divide by 2 and get 10.
.2/2=x/100
it is 90% smaller than 2b.
.56b is 28% of 2b because .56 multiplied by 100 is 56 then divide by 2 and you get 28.
.56/2=x/100
it is 72% smaller than 2b.
1.8b is 90% of 2b because 1.8 multiplied by 100 is 180 then divide it by 2. you get 90.
1.8/2=x/100
it is 10% smaller than 2b.
2.5b is 125% of 2b because 2.5 multiplied by 100 Is 250 and 250 divided by 2 is 125.
2.5/2=x/100
it is 25% larger than 2b
3b is 150% of 2b because 3 multiplied by 100 is 300 and 300 divided by 2 is 150.
3/2=x/100
it is 50% larger than 2b
Answer:
a. y equals one third times x plus 10
= y = 1/3(x) + 10
Step-by-step explanation:
Let us represent:
Let the original final plan = x
Let the current flight plan = y
The initial time of departure = 4.00pm
Her flight was then delayed for 10 minutes
We are told in the question that:
The current flight plan allows her arrive at her destination three times faster.
This means y= (1/3)x
y = x/3
Hence the equation generated =
y = x/3 +10
y = 1/3(x) + 10
