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2 years ago

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mikisha traveled from tampa to Miami a distance of 280 miles on one tank of gas if her tank holds about 13 gallons of fas ehat w

as her mile per gallon rate to the nearest whole number

2 answers:

Aleks [24]2 years ago

8 0

I will send someone too help you

bagirrra123 [75]2 years ago

3 0

I don't understand the question some misspelled words

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A new computer has a model number, a part number, and a serial number. The model number is assigned by the manufacturer to ident

kumpel [21]

<span>(serial number, model number)

That's a function mapping each serial number to its model number.

(part number, serial number)

That's not a function; the same part number is in computers with different serial numbers

</span><span> (model number, part number)
</span><span>
That one's a bit confusing. Normally a given model would have more than one part number inside so this isn't a function. But here the description says there's only one part number for each model, so that would be a function.

(model number, serial number)

Not a function, more than one serial number for a given model number.

</span>

4 0

2 years ago

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

a

The 95% confidence interval is $0.0503 < p < 0.1297$

b

The sample proportion is $\r p = 0.09$

c

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

d

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

2 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

2 years ago

Consider the table showing the given, predicted and residual values for a data set. A 4-column table with 4 rows. The first colu

Alecsey [184]

Answer:

Step-by-step explanation: I believe the answer would be (4, 0.1).

When plotting a residual, use the x-value, in this case 4, and the residual value as the y. (4, 0.1) The 4 is the x value, and the 0.1 replaces the y value. In the table the column headers will show you what the x, y, and residuals are. Just disregard the y-value and "predicted" and "given" columns, they are not needed when plotting the residual. I really hope this helps, and I hope I explained it well!

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2 years ago

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Jessica drinks 56 cup of milk for breakfast every day. How many cups of milk has Jessica drunk after 8 days?

Tom [10]

56 x 8 = 448

she drinks 448 cups of milk after 8 days

4 0

2 years ago

Read 2 more answers