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Neko [114]
1 year ago
12

Hi, I need help asap.

Mathematics
1 answer:
azamat1 year ago
3 0

part a) draw two triangles, translating one of them to the right.

part b) Consider triangles ΔYXB and ΔYZA. In these triangles:

  • ∠Y is common, then ∠XYB≅∠ZYA (additional information that is needed);
  • ∠YXB≅∠YZA (given);
  • XY≅ZY (given).

Therefore, these two triangles have two congruent angles adjacent to congruent sides. By the ASA Postulate, ΔYXB≅ΔYZA.

ASA Postulate: If two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the triangles are congruent.

part c) flow chart proof:

\triangle YXB\cong \triangle YZA\Rightarrow

  • XY≅ZY (given);
  • XB≅ZA (implies);
  • YB≅YA (implies).

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Step-by-step explanation:

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Step-by-step explanation:

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It is claimed that 55% of marriages in the state of California end in divorce within the first 15 years. A large study was start
kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that p = 0.55

Suppose 10 marriages are randomly selected.

This means that n = 10

What is the probability that less than two of them ended in a divorce?

This is

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042

P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045

0.0045 = 0.45% probability that less than two of them ended in a divorce

8 0
1 year ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

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Answer:

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8 - 6.99 = 1.01

1.01>0.99

So it's A

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