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Alex17521 [72]
2 years ago
12

Represent 23/-4 on number line

Mathematics
2 answers:
Dmitrij [34]2 years ago
5 0
\frac{23}{-4}=-5\frac{3}{4}

yulyashka [42]2 years ago
3 0
- 23/4 = -5.75


            -  6                           - 3                       0          1 
_________I__I______________I_______________I______I_____
                 - 23/4
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A teacher gives a test to a large group of students. The results are closely approximated by a normal curve. The mean is 74​, wi
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Answer:

Step-by-step explanation:

Given that a teacher  gives a test to a large group of students. The results are closely approximated by a normal curve

mu =74 and sigma =8

A grade starts from 100-8 = 92nd percentile

Z score for 92nd percentile = 1.405

X score = 74+8(1.405) = 85.24

--------------------

B cut off is to next 16%

Hence C would start for scores below 100-(8+16) = 76%

76th percentile = 0.705*8+74 =79.64

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2 years ago
Consider all seven-digit numbers that can be created from the digits 0-9 where the first and last digits must be odd and no digi
Natali [406]

Answer:

Considering all seven-digit numbers that can be created from the digits 0-9 I could deduce that you can make 100 , 700, 800 even infinite numbers

6 0
2 years ago
A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s
kondaur [170]
Hello,

g=9.81m/s²= 9.81/0.3048 =32.18.. ft/s² rounded to 32

h=-g/2*t²+vt+h0
if t=0,h=0 ==>h0=0

==>h=-16*t²+vt
50 ft in 2.5s ==> 25 ft in 1.25s

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==>v=50/1.25=40

Equation h=-16t²+40*t
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2 years ago
If the sample space S is an infinite set, does this necessarily imply that any random variable X defined from S will have an inf
alekssr [168]

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4 0
2 years ago
Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw
NISA [10]

Answer:

(1) Correct option (A).

(2) The probability that Aadi will get Tails is 0.40.

Step-by-step explanation:

The information provided is:

  • Eric throws a biased coin 10 times. He gets 3 tails.
  • Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

P(T|E)=\frac{3}{10}=0.30

P(T|S)=\frac{20}{50}=0.40

Here,

P (T|E) implies the probability of tail in case of Eric's experiment.

P (T|S) implies the probability of tail in case of Sue's experiment.

(1)

Now, it is given that Aadi is going to throw the coin once.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the probability of Aadi getting Tails in a single toss.

As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

P(\text{Aadi will get Tails})=P(T|A)

                                   =P(T|S)\\\\=0.40

Thus, the probability that Aadi will get Tails is 0.40.

8 0
2 years ago
Read 2 more answers
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