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saw5 [17]
2 years ago
6

A. If a spacecraft was parked on Venus and needed to make a flight to Jupiter, how far would it need to travel? Show your work a

nd provide your answer in scientific notation.
B. Mercury, Venus, and Earth are the three planets closest to the Sun. Would their combined distance from the Sun be greater or less than the distance from the sun to Neptune? Show your work and justify your answer.
C. If Earth was 10 times farther away from the Sun than it is now, which planet would it be closest to? Compare Earth's new distance to that planet. How far apart would they be in standard notation? How far apart in scientific notation? Show your work.
D. The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to reach Saturn from Earth. Show your work. Convert your answer into scientific notation if necessary.
Mathematics
1 answer:
bija089 [108]2 years ago
4 0
A. (Assume both planets are aligned with the sun and are on the same side of the sun.) Show your work and provide your answer in scientific notation. Jupiter = 778,500,000 km from sun. Venus = 108,200,000 km from sun.

778,500,000 – 108,200,000 = 670,300,000
It would need to travel 670,300,000 km/ 6.703 x 10 with a 8 squared km (as shown below)
10 {}^{8}


B.Mercury, Venus, and Earth are the three planets closest to the sun. Would their combined distance from the sun be greater or less than the distance from the sun to Neptune? Show your work and justify your answer. Mercury = 57,909,000 km Venus = 108,200,000 km Earth = 149,600,000 km 57,909,000 + 108,200,000 + 149,600,000 = 315,709,000 Less because 315,709,000 km is less than 4,498,000,000 km

C.If Earth was 10 times farther away from the sun than it is now, which planet would it be closest to? (Assume all the planets are aligned with the sun and are on the same side of the sun.) Compare Earth's new distance to that planet. How far apart would they be in standard notation? How far apart in scientific notation? Show your work. Earth = 149,600,000 km 149,600,000 x 10 = 1,496,000,000 Earth’s new distance = 1,496,000,000 Earth would be closest to Saturn. 1,496,000,000 – 1,429,000,000 = 67,000,000
They would be 67,000,000 km apart
Scientific notation: 6.7 x 10 with a 7 squared km (sorry I can't write this to show this figure but see below as you should write it exactly like how I typed it below followed by km)
10 {}^{7}


D. The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to reach Saturn from Earth. (Assume both planets are aligned with the sun and are on the same side of the sun.) Show your work. Convert your answer into scientific notation if necessary. Earth = 149,600,000 km
Saturn = 1,429,000,000 km
1,429,000,000 - 149,600,000 = 1,279,400,000
1,279,400,000 km
1,279,400,000 ÷ 28,000 = 45,692.8
Estimated hours it will take the shuttle to reach Saturn from Earth = 45,693
Scientific notation: 4.5693 x 10 with a 4 squared
(same with this one, it should be written as I have it shown below instead of how I first tried to explain it.)
10 {}^{4}






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stepan [7]
The decay rate should have units, it should be negative and it should be 100 times smaller than what you posted.
k = -.000124 / years

k = -.000124 / years
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.000124
Half-Life = <span> <span> <span> 5589.8951612903 </span> </span> </span>
Half-Life = 5,590 (rounded)

elapsed time = half-life * log(bgng amt / end amt) / log(2)
elapsed time = 5,590 * log(10) / <span> <span> <span> 0.3010299957 </span> </span> </span>
elapsed time = 5,590 * 1 / <span> <span> 0.3010299957 </span>
</span>elapsed time = <span> <span> <span> 18,569 years

</span></span></span>Source:
http://www.1728.org/halflife.htm



5 0
2 years ago
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Dorrian graphed the distance, y, traveled by 2 bikes in x seconds. If the two bikes are racing a distance of 100 feet, which bik
torisob [31]

Answer:

The bike whose position has greater y-coordinate.

Step-by-step explanation:

If Dorrian plotted the co-ordinates of the bikes with second on the x-axis and distance traveled on the y-axis, the x-coordinates of the two bikes will be the same.

But, the bike which went faster will have the greater y-coordinate and which followed the earlier will have the smaller y-coordinate.

Hence, the bike which has greater y-coordinate will win the race.

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2 years ago
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Mrs jones has ducks and sheep on her farm. The animals have a total of 6 heads and 16 legs. How many ducks does mrs jones have?
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4 ducks (4 heads, 8 legs) and 2 sheep (2 heads, 8 legs). Altogether, 6 heads and 16 legs.
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2 years ago
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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Nataliya [291]

Answer:

(a) Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = 0.15716

(b) Probability that a standard normal random variable will be between .3 and 3.2 = 0.3814

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with;

    Mean, \mu = 30.05 inches        and    Standard deviation, \sigma = 0.2 inches

Let X = A sheet selected at random from the population

Here, the standard normal formula is ;

                  Z = \frac{X - \mu}{\sigma} ~ N(0,1)

(a) <em>The Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = P(30.25 < X < 30.65) </em>

P(30.25 < X < 30.65) = P(X < 30.65) - P(X <= 30.25)

P(X < 30.65) = P(\frac{X - \mu}{\sigma} < \frac{30.65 - 30.05}{0.2} ) = P(Z < 3) = 1 - P(Z >= 3) = 1 - 0.001425

                                                                                                = 0.9985

P(X <= 30.25) = P( \frac{X - \mu}{\sigma} <= \frac{30.25 - 30.05}{0.2} ) = P(Z <= 1) = 0.84134

Therefore, P(30.25 < X < 30.65) = 0.9985 - 0.84134 = 0.15716 .

(b)<em> Let Y = Standard Normal Variable is given by N(0,1) </em>

<em> Which means mean of Y = 0 and standard deviation of Y = 1</em>

So, Probability that a standard normal random variable will be between 0.3 and 3.2 = P(0.3 < Y < 3.2) = P(Y < 3.2) - P(Y <= 0.3)

 P(Y < 3.2) = P(\frac{Y - \mu}{\sigma} < \frac{3.2 - 0}{1} ) = P(Z < 3.2) = 1 - P(Z >= 3.2) = 1 - 0.000688

                                                                                           = 0.99931

 P(Y <= 0.3) = P(\frac{Y - \mu}{\sigma} <= \frac{0.3 - 0}{1} ) = P(Z <= 0.3) = 0.61791

Therefore, P(0.3 < Y < 3.2) = 0.99931 - 0.61791 = 0.3814 .

 

3 0
2 years ago
Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was \$43.25$43.25dollar sign, 43,
Elodia [21]

Answer:

29 minutes

Step-by-step explanation:

Given

Total = \$43.25

Entrance\ Fee = \$7

Per\ Minute = \$1.25

Required

Determine the number of minutes (t) that he was on the trampoline.

This can be expressed as:

Total\ Payment = Entrance\ Fee + Amount\ per\ minute * t

Where t represents the number of minutes

Substitute values for Total, Entrance Fee and Amount per minute

43.25 = 7 + 1.25 * t

43.25 = 7 + 1.25t

Solving further to get the value of t, we have:

1.25t = 43.25 - 7

1.25t = 36.25

t = 36.25/1.25

t = 29

3 0
1 year ago
Read 2 more answers
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