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Natalka [10]
2 years ago
13

Find the first four iterates of the function f(z)=z^2+2+i with the initial value of z0=2+2i

Mathematics
2 answers:
r-ruslan [8.4K]2 years ago
4 0

B is the answer to the problem

IgorC [24]2 years ago
3 0

Answer:

so what's the answer?

Step-by-step explanation:

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A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl
sweet-ann [11.9K]

Answer:

E = 0 x (4/6) + 60 x (1/6) + 120 x (1/6)  = 30

Step-by-step explanation:

5 0
1 year ago
Read 2 more answers
(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>​
yan [13]

Answer:

h=588

Step-by-step explanation:

Given the fraction \dfrac{4,704}{h}

Consider its numerator and factor it:

4,704=2^5\cdot 3\cdot 7^2

You cann not take the cube root from 3, 7^2, 2^5, you can only take the cube root from 2^3, then the smallest whole number h such that \dfrac{4,704}{h} is a cube number is

h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588

When h=588,

\dfrac{4,704}{588}=8=2^3

6 0
1 year ago
The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T
Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. In this problem, \sigma = 0.25

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 1.96*\frac{0.25}{\sqrt{n}}

0.1\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.1}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

n = 24.01

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

M = z*\frac{\sigma}{\sqrt{n}}

0.06 = 1.96*\frac{0.25}{\sqrt{n}}

0.06\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.06}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}

n = 66.7

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.96*\frac{0.25}{\sqrt{n}}

0.05\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.05}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}

n = 96.04

Rounding up, 97

8 0
1 year ago
A graph in which the frequency for each category of a quantitative variable is represented as a vertical column that touches the
Arturiano [62]

Answer:

Histogram.

Step-by-step explanation:

Such a Graph is called Histogram.

A histogram can be defined as a visual representation of data in form of bars of different heights. In histogram, each and every bar groups numbers into ranges. The greater the height of the bar, the larger the data falls into its range. It basically represents shape and spread of continuous data sample.

3 0
1 year ago
In the diagram of circle o, what is the measure of ABC?<br> 27°<br> 54°<br> 108°<br> 120°
Vlad1618 [11]

<u>Given</u>:

Given that a circle O with two tangents BA and BC.

The major arc AC is 234°

The minor arc AC is 126°

We need to determine the measure of ∠ABC

<u>Measure of ∠ABC:</u>

We know the property that, "if a tangent and a secant, two tangents or two secants intersect in the interior of the circle, then the measure of angle formed is one half the difference of the measures of the intercepted arcs."

Hence, applying the above property, we have;

\angle ABC=\frac{1}{2}( major \widehat{AC} - minor \widehat{AC})

Substituting the values, we get;

\angle ABC=\frac{1}{2}( 234^{\circ} -126^{\circ})

\angle ABC=\frac{1}{2}( 108^{\circ})

\angle ABC=54^{\circ}

Thus, the measure of ∠ABC is 54°

Hence, Option b is the correct answer.

5 0
1 year ago
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