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Ostrovityanka [42]
2 years ago
8

A boy climbs to the top of a tree and sees his friend 100 feet from the base of the tree. If the tree is 25 feet tall, what is t

he angle of depression to his friend?
Mathematics
1 answer:
QveST [7]2 years ago
7 0
It would be helpful to draw the figure for this system. We would see that a right triangle is made where the base is equal to 100 ft and the height is equal to 25 ft. Using trigonometric functions we can easily calculate for the angle as follows:

tan (theta) = 25 / 100
theta = 14.04 degrees
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Helpp!!!? need help quick ..
stealth61 [152]
Note that

n^m*n^r=n^(m+r)

2^5*2^x=2^(5+x)

the answer is D
7 0
2 years ago
A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the n
AVprozaik [17]
X number of male students
Y number of female students
Z number of the adults
X=(1 + 7)Z=8Z
Y= X/2
X +Y +Z = 82
8Z +8Z/2 +Z=82 implies Z=82/26=3.1
so we take Z= 3

X= 24
and Y = 12







5 0
2 years ago
Colin & Brian share a lottery win of £2100 in the ratio 4 : 1. Colin then shares his part between himself, his wife & th
Paraphin [41]

Answer:

His wife gets $336 more than his son.

Step-by-step explanation:

Colin and Brian:

Ratio of 4:1.

So Colin gets \frac{4}{4+1} = \frac{4}{5} of the prize.

\frac{4*2100}{5} = 1680

Colin got $1680. Dividing between himself, his wife and their son:

Ratio of 2:5:3.

So Colin gets \frac{2}{2+3+5} = \frac{2}{10}, his wife gets \frac{5}{2+3+5} = \frac{5}{10} and his son gets \frac{3}{2+3+5} = \frac{3}{10}

Wife:

\frac{5*1680}{10} = 840

His wife got $840.

Son:

\frac{3*1680}{10} = 504

His son got $504.

How much more does his wife get over their son?

840 - 504 = 336

His wife gets $336 more than his son.

8 0
1 year ago
Yvette exercises 14 days out of 30 in one month. What is the ratio of the number of days she exercises to the number of days in
Anestetic [448]

Answer:

7 to 15, 7:15, 7/15

Step-by-step explanation:

Ratios can be written as:

a to b

a:b

a/b

We want to find the ratio of exercise days to days in the month. She exercises 14 days out of 30 days in the month. Therefore,

a= 14

b= 30

14 to 30

14:30

14/30

The ratios can be simplified. Both numbers can be evenly divided by 2.

(14/2) to (30/2)

7 to 15

(14/2) : (30/2)

7:15

(14/2) / (30/2)

7/15

3 0
2 years ago
Read 2 more answers
A sailboat is sitting at rest near its dock. A rope attached to the bow of the boat is drawn in over a pulley that stands on a p
irina [24]

Answer:

The boat is approaching the dock at rate of 2.14 ft/s

Step-by-step explanation:

The situation given in the question can be modeled as a triangle, please refer to the attached diagram.

A rope attached to the bow of the boat is drawn in over a pulley that stands on a post on the end of the dock that is 5 feet higher than the bow that means x = 5 ft.

The length of rope from bow to pulley is 13 feet that means y = 13 ft.

We know that Pythagorean theorem is given by

x^{2} + y^{2} = z^{2}

Differentiating the above equation with respect to time yields,

2x\frac{dx}{dt}  + 2y\frac{dy}{dt} = 2z\frac{dz}{dt}

x\frac{dx}{dt}  + y\frac{dy}{dt} = z\frac{dz}{dt}

dx/dt = 0  since dock height doesn't change

y\frac{dy}{dt} = z\frac{dz}{dt}

\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}

The rope is being pulled in at a rate of 2 feet per second that is dz/dt = 2 ft/s

First we need to find z

z² = (5)² + (13)²

z² = 194

z = √194

z = 13.93 ft

So,

\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}

\frac{dy}{dt} = \frac{13.93}{13}(2)

\frac{dy}{dt} = 2.14 ft/s

Therefore, the boat is approaching the dock at rate of 2.14 ft/s

8 0
2 years ago
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