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Nezavi [6.7K]
2 years ago
13

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0
(g-f)(x)=g(x)=f(x)

(g-f)(x)=6x-4+x^2

(g-f)(x)=x^2+6x-4  then:

(g-f)(3)=3^2+6*3-4

(g-f)(3)=9+18-4

(g-f)(x)=23
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Answer:

This statement can be made with a level of confidence of 97.72%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.1 mm

Standard Deviation, σ = 0.5 mm

Sample size, n = 100

We are given that the distribution of thickness is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.5}{\sqrt{100}} = 0.05

P(mean thickness is less than 8.2 mm)

P(x < 8.2)

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Calculation the value from standard normal z table, we have,  

P(x < 8.2) =0.9772 = 97.72\%

This statement can be made with a level of confidence of 97.72%.

8 0
2 years ago
Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height
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The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

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y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



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Answer:

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Step-by-step explanation:

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Denise is constructing A square in which two of its vertices are points M and N. She has already used her straightedge and compa
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Denise is constructing A square.

Note: A square has all sides equal.

We already given two vertices M and N of the square.

And another edge of the square is made by from N.

Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.

Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>

Therefore, correct option is :

D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.

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Answer:

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