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2 years ago

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Mathematics

1 answer:

SVEN [57.7K]2 years ago

7 0

(g-f)(x)=g(x)=f(x)

(g-f)(x)=6x-4+x^2

(g-f)(x)=x^2+6x-4 then:

(g-f)(3)=3^2+6*3-4

(g-f)(3)=9+18-4

(g-f)(x)=23

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Fruit juice comes in two types of containers. The first is a rectangular prism that is 9 inches tall and has a rectangular base

My name is Ann [436]

The volume of a rectangular prism:

$V_p=Bh\\\\B=wl\\\\w=2\ in;\ l=3\ in;\ h=9\ in$

substitute

$V_p=2\cdot3\cdot9=54\ in^3$

The volume of a cylinder:

$V_c=\pi r^2h\\\\r=1.5\ in;\ h=8\ in$

substitute:

$V_c=\pi\cdot(1.5)^2\cdot8=\pi\cdot2.25\cdot8=18\pi\ in^3\approx18\cdot3.14=56.52\ in^3$

Answer: C. The cylinder has the greater volume.

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2 years ago

Central school is hosting a “central has talent” show. They will award various prizes for the best 3 acts in the show. First pla

Serjik [45]

Well you didn't post the expressions but let X be the amount of money for first place. This means X-50 would be the amount of second place because each subsequent place after 1st wins $50 less than the previous place. Thirds, would be X-50-50 or X-100

Thus the total amount of money would be all of the values combined which is X+X-50+X-100=3X-150

8 0

2 years ago

What is the surface area of the right cone below?

maksim [4K]

Answer:

$SA=54\pi\ units^2$

Step-by-step explanation:

we know that

The surface area of the cone is given by the formula

$SA=\pi r^{2}+\pi rl$

where

r is the radius of the base

l is the slant height

we have

$r=3\ units\\l=15\ units$

substitute

$SA=\pi (3)^{2}+\pi (3)(15)$

$SA=54\pi\ units^2$

6 0

2 years ago

A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un

Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, assuming a significance level 0.1

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

$H_{0}:$ p1=p2

$H_{a}:$ p1≠p2

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }$ where

p1 is the sample proportion of West University students who involved in a car accident within the past year (0.15)
p2 is the sample proportion of East University students who involved in a car accident within the past year (0.12)

p is the pool proportion of p1 and p2 ( $\frac{15+12}{100+100}=0.135$ )
n1 is the sample size of the students from West University (100)
n2 is the sample size ofthe students from East University (100)

Then we have z= $\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } }$ ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

Assuming significance level 0.1, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

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2 years ago

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insens350 [35]

C .) The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.

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2 years ago

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