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jek_recluse [69]
2 years ago
11

Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution. What is th

e probability that a randomly selected student has a typing speed of less than 51 words per minute if the mean is 47 words per minute and the standard deviation is 4 words per minute
Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
8 0

Answer: 0.8413

Step-by-step explanation:

Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.

Mean : \mu=47

Standard deviation : \sigma= 4

Let x be the random variable that represents the typing speeds for the students.

The z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 51

z=\dfrac{51-47}{4}=1

Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-

P(x

Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413

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12. A cyclist travels 40 km at a speed of x km/h. Find the time
GREYUIT [131]

Answer:

Step-by-step explanation:

distance = rate times time, so

           

           distance

time = --------------

               rate

Here the distance is 40 km and the rate is x.  Then

              40 km

time = --------------  =  (40/x) hr

             x km/hr

If the speed is reduced by 2 km/hr, we get:

              40 km                                            40 km                  40

time = -------------------------------  or time = ----------------------- = --------- hr

             (x km/hr - 2 km/hr)                      (x - 2) (km/hr)       x - 2

The difference between the times is:

 40          40

-------- - --------- = 1 hr          Solve this for the original speed, x

x - 2         x

40x - 40x + 80                                80

-----------------------  =  1 hr     or     ------------ = 1     or 80 = x^2 - 2x

     x(x - 2)                                     x(x - 2)

Rewriting this in standard quadratic form:  x^2 - 2x - 80 = 0

Here a = 1, b = -2 and c = -80, and so the discriminant b^2 - 4ac is:

(-2)^2 - 4(1)(-80) = 324

The solutions are:

   

      -(-2) ± √324       2 ± 18

x = -------------------- = ------------ = 1 ± 9, or 10 (discard the other root)

              2                      2

The original speed was 10 km/hr

7 0
2 years ago
Read 2 more answers
Luke has 1/5 of a package of dried apricots. He divides the dried apricots equally into 4 small bags. Luke gives one of the bags
Ivahew [28]

Answer:

3/80

Step-by-step explanation:

If one fifth of apricots are split into 4 parts, each bag has 1/5 * 1/4 of the original apricots

1/5 * 1/4 = 1/20

Luke keeps 3/4 of those so that's

3/4 * 1/20 = 3/80

7 0
2 years ago
Match the following guess solutions ypyp for the method of undetermined coefficients with the second-order nonhomogeneous linear
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

1 ) Given that

(d^2y/dx^2) + 4y = x - x^2 + 20\\\\ (d^2y/dx^2) + 4y =  - x^2 + x + 20

For a non homogeneous part - x^2 + x + 20 , we assume the particular solution is

y_p(x) = Ax^2 + Bx + C

2 ) Given that

d^2y/dx^2 + 6dy/dx + 8y = e^{2x}

For a non homogeneous part   e^{2x} , we assume the particular solution is

y_p(x) = Ae^{2x}

3 ) Given that

y′′ + 4y′ + 20y = −3sin(2x)

For a non homogeneous part −3sin(2x) , we assume the particular solution is

y_p(x) =  Acos(2x)+Bsin(2x)

4 ) Given that

y′′ − 2y′ − 15y = 3xcos(2x)

For a non homogeneous part  3xcos(2x)  , we assume the particular solution is

y_p(x) = (Ax+B)cos2x+(Cx+D)sin2x

4 0
2 years ago
Match each three-dimensional figure to its volume based on the given dimensions. (Assume π = 3.14.)
LekaFEV [45]

Answer:

The volume of the cylinder is 150.72 cm³ ⇒ last answer

The volume of the cone is 314 cm³ ⇒ 1st answer

The volume of the pyramid is 160 cm³ ⇒ 2nd answer

The volume of the pyramid is 48 cm³ ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the volumes of some shapes

- The volume of the cylinder of radius r and height h is:

 V = π r² h

- The volume of the cone of radius r and height h is:

 V = 1/3 π r² h

- The volume of the pyramid is:

 V = 1/3 × its base area × its height

* Lets solve the problem

# A cylinder with radius 4 cm and height 3 cm

∵ V = π r² h

∵ π = 3.14

∵ r = 4 cm , h = 3 cm

∴ v = 3.14 (4)² (3) = 150.72 cm³

* The volume of the cylinder is 150.72 cm³

# A cone with radius 5 cm and height 12 cm

∵ V = 1/3 π r² h

∵ π = 3.14

∵ r = 5 cm , h = 12 cm

∴ V = 1/3 (3.14) (5)² (12) = 314 cm³

* The volume of the cone is 314 cm³

# A pyramid with base area 16 cm² and height 30 cm

∵  V = 1/3 × its base area × its height

∵ The area of the base is 16 cm²

∵ The height = 30 cm

∴ V = 1/3 (16) (30) = 160 cm³

* The volume of the pyramid is 160 cm³

# A pyramid with square base of length 3 cm and height 16 cm

∵  V = 1/3 × its base area × its height

∵ The area of the square = s²

∵ The area of the base = 3² = 9 cm²

∵ The height = 16 cm

∴ V = 1/3 (9) (16) = 48 cm³

* The volume of the pyramid is 48 cm³

3 0
2 years ago
Read 2 more answers
Which are correct representations of the inequality -3(2x - 5) <5(2 - x)? Select two options.
Sonja [21]

Answer:

The third and fourth options.

Step-by-step explanation:

You simplify the inequality first...

-6x + 15 < 10 - 5x

-x < -5

x > 5

The first option is incorrect since it is less than.

The second option is basically -5x < 15; x > -3; that's incorrect.

The third option is basically -x < -5; x > 5; that is correct!

The fourth option is correct since it shows more than 5.

The fifth option is incorrect because it shows less than -5.

Hope this helps!

5 0
2 years ago
Read 2 more answers
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