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Ludmilka [50]
1 year ago
8

The cafe where you work just ran out of coffee, and you are at the store to buy 112 pounds of coffee. You have put a can with 34

pound of coffee into your shopping cart. How many more pounds of coffee do you need?
Mathematics
2 answers:
ycow [4]1 year ago
7 0

Answer:

78

Step-by-step explanation:

The total you are buying is 112 pounds.  The can you have picked up is 34 pounds; this leaves

112-34 = 78 pounds remaining.

jeka941 year ago
4 0
You have to use subtraction to answer this question. 112-34=78 So, you still need 78 pounds of coffee
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A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The
lisov135 [29]

Answer:

(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96

(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96

And the confidence interval would be given by:

-1.96 \leq \mu_1 -\mu_2 \leq 7.96

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

Step-by-step explanation:

For this case we have the following info given :

\bar X_1= 75.1 represent the sample mean for the scores of the undergraduate students

s_1 = 12.8 represent the standard deviation for the undergraduate students

n_1 =35 the sample size for the undergraduate

\bar X_2= 72.1 represent the sample mean for the scores of the high school students

s_2 = 14.6 represent the standard deviation for the high school students

n_2 =50 the sample size for the high school

The confidence interval for the true difference of means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom are given by:

df=n_1 +n_2 -2= 35+50-2=83

The confidence level is 90% and the significance level is \alpha=0.1 and \alpha/2 =0.05 then the critical value would be:

t_{\alpha/2}= 1.99

And replacing the info we got:

(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96

(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96

And the confidence interval would be given by:

-1.96 \leq \mu_1 -\mu_2 \leq 7.96

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

8 0
1 year ago
For which values of a the system has no solution: x≤5, x≥a
soldi70 [24.7K]

Given:

The system of inequalities is

x\leq 5

x\geq a

To find:

The values of a for which the system has no solution.

Solution:

We have,

x\leq 5        ...(1)

It means the value of x is less than or equal to 5.

x\geq a        ...(2)

It means the value of x is greater than or equal to a

Using (1) and (2), we get

a\leq x\leq 5

But if a is great than 5, then there is no value of which satisfies this inequality.

Therefore, the system has no solution for a>5.

7 0
2 years ago
Hailey is shopping at a department store during a 20% off everything sale. She also has a coupon for $5.00 off the sale amount.
Kipish [7]

Possible inequality:

= x\leq 87.50

4 0
1 year ago
Read 2 more answers
Find the dimensions of a deck which will have railings on only three sides. There is 28 m of railing available and the deck must
Roman55 [17]

Answer:

The largest possible area of the deck is 87.11 m² with dimensions;

Width = 9.33 m

Breadth = 9.33 m

Step-by-step explanation:

The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square

Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area

The length of the given railing = 28 m

The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each

The area of a square of side s = s²

The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;

Width = 28/3 m = 9.33 m

Breadth = 28/3 m = 9.33 m.

5 0
2 years ago
The size of angle aob is equal to 132 degrees and the size of angle cod is equal to 141 degrees. find the size of angle dob.
Varvara68 [4.7K]

angle AOB = 132 and is also the sum of angles AOD and DOB. Hence 
angle AOD + angle DOB = 132°    ---> 1 

angle COD = 141 and is also the sum of angles COB and BOD. Hence 
angle COB + angle DOB = 141°    ---> 2

Now we add the left sides together and the right sides of equations 1 and 2 together to form a new equation. 

angle AOD + angle DOB + angle COB + angle DOB = 132 + 141       ---> 3 

We should also note that: 
angle AOD + angle DOB + angle COB = 180° 

Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180 and solving for angle DOB:
180 + angle DOB = 132 + 141 
angle DOB = 273 - 180 = 93° 

8 0
2 years ago
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