At Tom's workplace, the thermometer is reading 86 degrees Fahrenheit.

Mathematics

1 answer:

Kryger [21]1 year ago

7 0

Answer:

16 degrees Celsius, with breaks at 172 degrees Fahrenheit.

Step-by-step explanation:

To calculate 86 degrees in Fahrenheit you need to take the 86 degrees you are given and first mulitply it by 5 over 9 (5/9). That will give you about 48 degrees. To finish solving it for celsius you then need to take your 48 and subtract 32, in which you would get 16. So, the temprature Tom needs to take a break at is 172 degrees Fahrenheit.

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Solve 5/3x + 1/3x = 13 1/3 + 8/3x then identify x.

belka [17]

After solving $\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x$ we get value of x = -20

Step-by-step explanation:

We need to solve the fractions and find value of x.

The given fraction is:

$\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x$

Solving:

$\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x\\\frac{5}{3}x+\frac{1}{3}x=\frac{40}{3}+\frac{8}{3}x\\ Subtract\,\,\frac{8}{3}x\,\,on\,\,both\,\,sides:\\ \frac{5}{3}x+\frac{1}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x\\Simplifying:\\ \frac{5x+1x-8x}{3}=\frac{40}{3}\\ \frac{-2x}{3}=\frac{40}{3}\\Multiply\,\,both\,\,sides\,\,by\,\,3\\-2x=40\\x=\frac{40}{-2}\\x=-20$

So, After solving $\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x$ we get value of x = -20

Keywords: Solving fractions

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2 years ago

lev has 9 tens. jim has 1 ten. they put all their tens together. dawn puts 9 ones with the tens. what number did they make?

MatroZZZ [7]

The answer to this 110

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2 years ago

Mark has a 25 ounce drink. He drinks 5 ounces. What percent of the drink does he have left?

valina [46]

Answer: $80\%$

Step-by-step explanation:

This problem can be solved by the <u>Rule of Three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this case, the 25 ounce drink represents the $100 \%$ . So, if Mark drinks 5 ounces, this means he has 20 ounces left and we have to find the percent this represents: