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inysia [295]
2 years ago
8

Lacinda has 120 ft of fencing to make a rectangular kennel for her dogs. The house is to be used as one side of the kennel. What

length will maximize the area of the kennel?
Mathematics
1 answer:
never [62]2 years ago
4 0

Answer:

1,800ft^{2}

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

A = L*W

Where

  1. A is the Area
  2. L is the length
  3. W is the width

Since the house wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the kennel we will need to equally divide the 120 ft of fencing between the Length and Width.

120 / 2 = 60ft

So We have 60 ft for the length and 60 ft for the width. Since the width has 2 sides we need to<u> divide 60 by 2</u>.

60/2 = 30 ft

Now we can calculate the maximum Area using the values above.

A = 60*30

A = 1800ft^{2}

So the Maximum area we are able to create with 120ft of fencing is 1,800ft^{2}

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Mashutka [201]

Answer:

0

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0

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2 years ago
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Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great
Y_Kistochka [10]

Answer:

56 cm

Step-by-step explanation:

We need ro find the GCD of these numbers. In finding the GCD, we list the multiples of the number, beginning with the smallest number. Here, the

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The factors of 448 =2*2*2*2*2*2*7

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6 0
2 years ago
The graph of a hyperbola is shown.
Veseljchak [2.6K]

Answer:the length of the transverse axis is 18 units. Option C is the correct answer

Step-by-step explanation:

The transverse axis is the line segment which passes through the center of the hyperbola and its endpoints are the vertices of the hyperbola. Looking at the diagram of the hyperbola given, it has two foci at - 15 and 15 on the x axis. It has two vertices at - 9 and 9 on the x axis. Therefore the length of the transverse axis is -9 to 9. It becomes

9 - - 9 = 18

4 0
2 years ago
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A rectangular Corn Hole area at the recreation center has a width of 5 feet and a length of 10 feet. If a uniform amount is adde
almond37 [142]
1. The formula for calculate the area of a rectangle, is:
 
 A=LxW
 
 A is the area of the rectangle
 L is the length of the rectangle.
 W is the widht of the rectangle

2. You have that:
 
 -The<span> rectangular Corn Hole area has a width of 5 feet and a length of 10 feet, so:
 
 L1=10 feet
 W1=5 feet
 
 - When</span> a uniform amount is added to each side (x), the area is increased to 84 feet². Then, you have a different length (L2) and a different width (W2):
 
 3. The new length is:<span> 
 
 L2=L1+x+x
 L2=L1+2x
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 4. The new width is:
 
 W2=W1+x+x
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 W2=5+2x
 
 5. The new area is:
 
 A2=84 feet</span>²<span>
 
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<span> 
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</span><span> 
</span>
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2 years ago
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Kamila [148]
Mike is 19.

If you turn the question into an equation it turns to:
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So since you don’t know Jasmine’s age you would use guess and check. 8,9, and 10 didn’t work but when you put in 11:
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And to check your work
J + M has to equal 30 so,
11 + 19 = 30
30 = 30
6 0
2 years ago
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