The first one is 13 points and the 2nd one is 8. I'm pretty sure, hope this helps! :)
<span>The answer is She should have multiplied by 2 instead of dividing by 2.
First one.</span>
Answer:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are:
Step-by-step explanation:
We don't know the distribution for the scores. But we know the following properties:
For this case we can use the Chebysev theorem who states that "At least 
of the values lies between 
and 
"
And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are:
Answer: 125
Step-by-step explanation:
Given that:
The principal = 15000
Rate = 10%
Years = 1 year = 12 month
Interest I = PRT/100
I = (15000 × 10 × 1)/100
I = 1500
The amount of interest expense that would they record in May will be
Interest = I/ 12 = 1500/12 = 125
Answer:
We have the functions:
f(x) = IxI + 1
g(x) = 1/x^3.
Now, we know that the composite functions do not permute.
How we can prove this?
First, two composite functions are commutative if:
f(g(x)) = g(f(x))
Well, you could use brute force (just replace the values and see if the composite functions are commutative or not)
But i will use a more elegant way.
We can notice two things:
g(x) has a discontinuity at x = 0.
so:
f(g(x)) = I 1/x^3 I + 1
still has a discontinuty at x = 0, but:
g(f(x)) = 1/( IxI + 1)^3
here the denominator is IxI + 1, is never equal to zero.
So now we do not have a discontinuity.
Then the composite functions can not be commutative.
