The problem statement gives the correct answers for parts (a) and (b). The total number of roots of the characteristic polynomial is the dimension of the matrix: 6. The eigenvalues are the zeros of the characteristic polynomial, 3 (multiplicity 2), 6 (multiplicity 3), and -1.
(c) The matrix is not invertible when one or more eigenvalues is zero. None of yours are zero, so the matrix is invertible.
I’m not entirely sure but the answer might be 72 1/2 miles. I added up 12 1/3, 8 3/4, 17 2/8, 23 2/3, and 10 5/10. And I got 72 1/2.
ANSWER
The correct option is,
EXPLANATION
We were given that the solutions of the quadratic equation are
and
This tells us that,
and
are factors of the quadratic equation.
This implies that the quadratic equation is of the form,
We were also told that
is a non zero constant.
This means that we can use k to multiply the whole equation and the solution will not be affected.
Our equation now becomes,
Hence the correct answer is A.
Answer:
Una relación lineal es de la forma:
y = a*x + b.
donde a es la pendiente y b es la ordenada al origen.
en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.
Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:
$21,000 = a*5 + $42,000
a*5 = $21,000 - $42,000 = -$21,000
a = -$21,000/5 = -$4,200
Esto significa que el precio decae $4,200 por año
Answer:
a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.
Step-by-step explanation:
The weight of the object in air is 8N,
and weight = Mass * acceleration due to gravity = m * 9.81
8/9.81 = 0.815,
upthrust( force acting on the body from the liquid impeding the immersion) on the body when fully submerged = weight in air - weight in water = 8N - 6N =2N
Upthrust = weight of water displaced = 2N = mass * acceleration
2/9.81 = 0.204kg
density of water(1000kg/m^3) = mass of water / volume of water
volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)
volume of water displaced = volume of the solid
density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3
b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N
c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.
