The table shows Mr. Winkler’s schedule for paying off his credit card balance. A 5-column table with 4 rows. Column 1 is labeled
2 answers:
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Answer:
segment EF ≅ segment GF because both segments are the same distance from the center of circle A ⇒ answer B
Step-by-step explanation:
* Lets revise some facts in the circle
- The perpendicular segment from the center of the circle to a chord
bisects it
- A segment from the center of a circle to the midpoint of a cord is
perpendicular to it
- Congruent chords in a circle are equidistant from the center of the circle,
that means the perpendicular distances from the center of the circle
to the chords are equal
- If two chords in a circle are equidistant from the center of the circle
<em>( the perpendicular distances from the center of the circle to the </em>
<em> chords are equal) </em>, then they are congruent
* Lets solve the problem
∵ ∠EDA is right angle
∵ AD ⊥ FE
∵ ∠GHA is right angle
∵ AH ⊥ FG
∵ AD = AH
∵ EF and GF are chords in the circle A
∴ The chords EF and GF are equidistant from the center of the circle A
- By using the bold fact above
∴ EF ≅ GF
* segment EF ≅ segment GF because both segments are the same
distance from the center of circle A
Answer:
d. Water Source Well City Water Stream Expected Count 45.33 45.33 45.33
Step-by-step explanation:
Hello!
The objective of this study is to test whether the horses are equally likely to get water from one of three sources (Well, City or Stream), i.e. that the water sources have the same probability of being used.
The study variable is categorical:
X: Origin of the drinking water of the horses, categorized: Well "W", City "C" and Stream "S"
And one study population:
"Horses"
If the study hypothesis is that the three water sources are equally to be selected, you can symbolize it as P(W)=P(C)=P(S)=1/3
You want to test if the observed distribution follows an expected distribution, the test to use is a Chi-Square Goodness of Fit Test.
The hypothesis is:
H₀: P(W)=P(C)=P(S)=1/3
Under the null hypothesis, the formula to calculate the expected frequencies is:
Where:
is the expected value of the i-category.
is the probability for the i-category under the null hypothesis.
n= sample size.
Observed frequencies:
Well: 62
City: 43
Stream: 31
Total: 136
Expected frequencies:
Typ, if the expected frequencies are correctly calculated, the sum of them must give the total of the sample (although depending on the type of approximation it can vary in one or two decimals)
45.33 * 3= 135.99 ≅ 136
I hope it helps!