Complete question:
Which equation accurately represents this statement? Check all that apply.
Negative 3 less than 4.9 times a number, x, is the same as 12.8
A: -3-4.9x=12.8
B: 4.9x-(-3)=12.8
C: 3+4.9x=12.8
D: (4.9-3)x=12.8
E: 12.8=4.9x+3
Answer:
B: 4.9x-(-3)=12.8
C: 3+4.9x=12.8
E: 12.8=4.9x+3
Step-by-step explanation:
The word equation can be expressed mathematically as follows
negative 3 → -3
less than 4.9 times a number , x → 4.9 x - (-3)
is same as 12.8 → 4.9 x - (-3) = 12.8
The equation can be expressed as
4.9 x - (-3) = 12.8
when you open the bracket, you multiply -3 time - 1 . MInus times minus is equals to plus. so you get
4.9 x + 3 = 12.8
12.8 = 4.9x+3
Answer:

Step-by-step explanation:
Given
Height = 10cm
<em>See Attachment for complete question</em>
Required
Determine the volume of the circle
The volume is calculated as thus;

Take
as 
<em>So; Volume becomes</em>

Substitute 10 for h


Since, the value of the radius is not given;
<em>The volume of the circle is:</em>

1. The first step is to realize you need to find a number that will be bigger than 74.
2. All you have to do for this problem is to divide 74 by 90%. You can put this in the calculator by typing in (74 / .9).
3. The answer you get should be 82.22
4. You can check this by multiplying 82.22 by 90%, and it should bring you back to 74.
Answer:
∠JKM = 42°
Step-by-step explanation:
Since M is in the interior of ∠JKL, then
∠JKM + ∠MKL = ∠JKL ← substitute values
∠JKM + 42 = 84 ( subtract 42 from both sides )
∠JKM = 42°
We are given dimensions of rectangular bedroom = length of 5m and width 3 m.
Also scale drawing of factor 1/50 of the original dimension.
In order to find the dimensions of scale drawing, we need to multiply scale factor by each dimension.
Therefore, length of the scale drawing is 5 * 1/50 = 1/10 m and
Let us convert it in centimeter now.
1 m = 100 cm
1/10 m = 100 * 1/10 = 10cm.
Width of the scale drawing = 3 * 1/50 = 3/50 m.
100*3/50 = 6 cm.
Therefore, the dimensions of a scale drawing of Elenas bedroom is length 10cm and width 6cm.