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Lera25 [3.4K]
2 years ago
12

A study of king penguins looked for a relationship between how deep the penguins dive to seek food and how long they stay underw

ater. For all but the shallowest dives, there is a linear relationship that is different for different penguins. The study report gives a scatterplot for one penguin titled, "The relation of dive duration (DD) to depth (D)." Duration DD is measured in minutes, and depth D is in meters. The report then says, "The regression equation for this bird is DD = 2.69 + 0.0138D.
(a) What is the slope of the regression line? (Enter your answer rounded to four decimal places.)
(b) On average, if the depth of the dive increases by one meter, what is the increase in the diving duration? (Enter your answer rounded to four decimal places.)
(c) According to the regression line, how long does a typical dive to a depth of 244 meters last? (Enter your answer rounded to three decimal places.)
Mathematics
1 answer:
Vesna [10]2 years ago
3 0

Answer:

a) m = 0.0138

b) 0.0138 minutes

c) 6.057 minutes

Step-by-step explanation:

We are given the following in the question:

The relation of dive duration (DD) to depth (D) is given by the regression equation:

DD = 2.69 + 0.0138D

Duration DD is measured in minutes, and depth D is in meters.

Here, DD is the dependent variable and D is the independent variable.

Comparing the equation to a linear equation, we have,

y = mx + c

where m is the slope of the equation and gives the rate of change and c is the y-intercept that is value of y when x is zero.

m = 0.0138

c = 2.69

a) slope of the regression line

The slope of the regression lines, m = 0.0138

b)  increase in the diving duration,  if the depth of the dive increases by one meter

DD(D) = 2.69 + 0.0138D\\DD(D+1) = 2.69 + 0.0138(D+1)\\\text{Subtracting the equations}\\DD(D+1)-DD(D) = 2.69 + 0.0138(D+1) - (2.69 + 0.0138D)\\DD(D+1)-DD(D) =  0.0138(D+1-D)\\DD(D+1)-DD(D) =  0.0138

Thus, On average, if the depth of the dive increases by one meter, 0.0138 minutes is the increase in the diving duration.

c) Duration of a typical dive to a depth of 244 meters

We put D = 244

DD = 2.69 + 0.0138(244)\\DD = 6.057\text{ minutes}

It takes 6.057 minutes for a dive of 244 minutes.

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Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

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The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

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To compute the probability of  Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

P(8.8

                           =P(-1.25

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

P(x_{1}

Compute the value of <em>z</em> as follows:

P(-z

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5     z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

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Let the width of the yard  be w.
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