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2 years ago

7. Certain car manufacturers install a gauge that tells the driver how many miles they can drive

Mathematics

1 answer:

nalin [4]2 years ago

5 0

Answer:

A) Slope - 1.1889. The Predicted distance the drivers were able to drive increases by 1.1889

Step-by-step explanation:

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Under what circumstances will the chi-square test for goodness of fit produce a large value for chi-square? Question options: a.

Whitepunk [10]

Answer:

a.when the sample proportions are much different than the hypothesized population proportions

Step-by-step explanation:

A chi-square test for goodness of fit is used to check the sample data were distributed according to claim or not.

If the chi-square test produces a large value of chi-square statistic then there is not a good fit between sample data and the null hypothesis. So, the sample proportions are much different than the hypothesized population proportions. Hence,Option (a) is correct.

If the goodness of fit produces a large value for chi-square then the sample means must not be close to the population mean. So, option (b) is incorrect.

4 0

2 years ago

Kevin ate 2 slices of cake. Ben ate 1 slice. If Kevin ate 2/6 of the cake and all the slices are the same size, what fraction of

Alexeev081 [22]

1/2 of the cake was eaten

1+2=3. 3/6=1/2

All the slices are the same size

3 0

1 year ago

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

$IQR=Q_3-Q_1=16-6.5=9.5$

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

$IQR=Q_3-Q_1=15.5-8=7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0

2 years ago

The line 3y+x=25 is a normal to the curve y=x2-5x+k.find the value of constant k.

ladessa [460]

Answer:

k = 11.

Step-by-step explanation:

y = x^2 - 5x + k

dy/dx = 2x - 5 = the slope of the tangent to the curve

The slope of the normal = -1/(2x - 5)

The line 3y + x =25 is normal to the curve so finding its slope:

3y = 25 - x

y = -1/3 x + 25/3 <------- Slope is -1/3

So at the point of intersection with the curve, if the line is normal to the curve:

-1/3 = -1 / (2x - 5)

2x - 5 = 3 giving x = 4.

Substituting for x in y = x^2 - 5x + k:

When x = 4, y = (4)^2 - 5*4 + k

y = 16 - 20 + k

so y = k - 4.

From the equation y = -1/3 x + 25/3, at x = 4

y = (-1/3)*4 + 25/3 = 21/3 = 7.

So y = k - 4 = 7

k = 7 + 4 = 11.

6 0

2 years ago

What is the period of the function f(x) shown in the graph?

MariettaO [177]

Answer:

(0,-2)

Step-by-step explanation:

4 0

1 year ago

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