Answer: The average number of hours she danced per day is 1.9 hours (rounded to the nearest tenth)
Step-by-step explanation: We start by calculating how many hours she danced all together which can be derived as follows;
Summation = 3 +2 +2 + 1 + 1.5 + 2 = 11.5
The number of days she danced which is the observed data is 6 days (she did not dance at all on Wednesday).
The average (or mean) hours she danced each day can be calculated as
Average = ∑x ÷ x
Where ∑x is the summation of all data and x is number of observed data
Average = (3+2+2+1+1.5+2) ÷ 6
Average = 11.5 ÷ 6
Average = 1.9166
Approximately, average hours danced is 1.9 hours (to the nearest tenth)
Anything to the power of 0 is one.
Therefore we have:
(1)(y^-7z)
Which simplifies to:
y^-7z
Answer:
the answer is 10
Step-by-step explanation:
If N is first and L is last, then we just need to find all of the permutations for M, O, and P
with first letter M: MOP MPO
with first letter O: OPM OMP
with first letter P: PMO POM
Now, place the N in front and the L at the end of each permutation. There are 6 permutations in total:
NMOPL NMPOL
NOPML NOMPL
NPMOL NPOML
Answer:
D(t) = 3 + 0.0(80 - t)
Step-by-step explanation:
The average of speed of Laura in miles per hour is given by:
S(t) = 6 + 0.1(80 - t) Equation 1
where, t is the temperature in degrees Fahrenheit.
The distance D, Laura covers at x miles per hour is given as:
D(x) = 0.5x Equation 2
We need to find the expression that models the distance that Laura runs in terms of the temperature "t"
The "x" in Equation 1 represents the average speed of Laura in miles per hour. S(t) in Equation 1 also represent the speed of Laura in miles per hour. So, we can replace x by S(t) in Equation 2 and generate an equation of Distance in terms of temperature "t" as shown below:
D(S(t)) = 0.5 (6 + 0.1(80-t))
D(t) = 3 + 0.0(80 - t)
This expression models the distance that Laura runs in 30 minutes given that it is t∘F outside at the start of her run.
