Answer: The correct option is second, a rotation clockwise about the origin followed by a reflection across the x-axis.
Explanation:
From the given figure it is noticed that the vertices of ΔABC are A(-6,4), B(-4,6), C(-2,2) and vertices of ΔA'B'C' are A'(4,-6), B(6,-4), C(2,-2).
It means if the point is P(x,y) then after transformation it will be P'(y,x).
If a point P(x,y) reflection across the y-axis followed by a reflection across the x-axis, then the image of point after transformation will be P'(-x,-y), therefore it is not the correct option.
If a shape is rotated clockwise about the origin then the point P(x,y) will be P'(y,-x) and after that reflect across the x-axis, so the point after transformation will be P'(y,x), therefore it is the correct option.
If a shape is rotated clockwise about the origin then the point P(x,y) will be P'(-y,x) and after that reflect across the x-axis, so the point after transformation will be P'(-y,-x), therefore it is not the correct option.
If a point P(x,y) reflection across the x-axis followed by a reflection across the y-axis, then the image of point after transformation will be P'(-x,-y), therefore it is not the correct option.
Hence, the correct option is second, a rotation clockwise about the origin followed by a reflection across the x-axis.
In the 5th year
<h2>Step-by-step explanation:</h2>For the first year, the salary is 1.2million = 1,200,000
For the second year, the salary is 1.2million + 75000 = 1,200,000 + 75,000 = 1,275,000
.
.
.
For the last year, the salary is 1.5million = 1,500,000
This gives the following sequence...
1,200,000 1,275,000 . . . 1,500,000
This follows an arithmetic progression with an increment of 75,000.
<em>Remember that,</em>
The last term, L, of an arithmetic progression is given by;
L = a + (n - 1)d ---------------(i)
<em>Where;</em>
a = first term of the sequence
n = number of terms in the sequence (which is the number of years)
d = the common difference or increment of the sequence
<em>From the given sequence,</em>
a = 1,200,000 [which is the first salary]
d = 75,000 [which is the increment in salary]
L = 1,500,000 [which is the maximum salary]
<em>Substitute these values into equation (i) as follows;</em>
1,500,000 = 1,200,00 + (n - 1) 75,000
1,500,000 - 1,200,000 = 75,000(n-1)
300,000 = 75,000(n - 1)
4 = n - 1
n = 5
Therefore, in the 5th year the maximum salary will be reached.