No way to tell . . . . . we can't see the chart below.
It must be WAY down there where the sun don't shine.
Answer:
There is a correlation between age and length of stay. There may or may not be causation. Further studies would have to be done to determine this.
Step-by-step explanation:
The answer was checked
For the second part, you have to subtract 1 from the number of hours and raise it to that power.
For example, when h = 1, you have:
2^(1 - 1)
2^0
1
The 5 values in your table would be:
1 2 4 8 16
The length of the line segment SR is 15 units ⇒ 3rd answer
Step-by-step explanation:
Let us revise the rules in the right angle triangle when we draw the perpendicular from the right angle to the hypotenuse
In triangle ABC
Angle B is a right angle and AC is the hypotenuse
BD ⊥ AC ⇒ perpendicular from the right angle to the hypotenuse
- (AB)² = AD × AC
- (BC)² = CD × AC
- (BD)² = AD × CD
- BD × AC = AB × BC
In Δ SRQ
∵ ∠SRQ is a right angle
∴ SQ is the hypotenuse
∵ RT ⊥ SQ
- By using the rules above
∴ (RQ)² = TQ × SQ
∵ RQ = 20 units and TQ = 16 units
- Substitute these values in the rule above
∴ (20)² = 16 × SQ
∴ 400 = 16 × SQ
- Divide both sides by 16
∴ SQ = 25 units
By using Pythagoras theorem in Δ SRQ
∵ (SR)² + (RQ)² = (SQ)²
∵ RQ = 20 units and SQ = 25 units
- Substitute these values in the rule above
∴ (SR)² + (20)² = (25)²
∴ (SR)² + 400 = 625
- Subtract 400 from both sides
∴ (SR)² = 225
- Take √ for both sides
∴ SR = 15 units
The length of the line segment SR is 15 units
Learn more:
You can learn more about right triangles in brainly.com/question/1238144
#LearnwithBrainly
Answer:
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
Step-by-step explanation:
To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.
Vcube = a³
Vsphere = (4*pi*r³)/3
Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:
Vcube = 15³ = 3375 cubic inches
Vsphere = (4*pi*(9.5/2)³)/3 = 448.921
The volume of foam there is needed to complete the box is the subtraction between the two volumes above:
Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
