There might be two ways to go about this
(1) I am going to assume that we can construct a second (reference) triangle - and you confirmed that it is ok to use trigonometry on that, and then we use the relationship between areas of similar triangles to get what we want. I choose a triangle DEF with same angles, 15, 75, and 90 degrees, and the hypotenuse DE a of length 1 (that is a triangle similar to ABC). I use sin/cos to determine the side lengths: sin(15)=EF and cos(15)=DF and then compute the area(DEF) =EF*DF/2. This turns out to be 1/8 = 0.125.
Now one can use the area formula for similar triangles to figure out the area of ABC - this without trigonometry now: area(ABC)/area(DEF)=(12/1)^2
so area(ABC)=144*area(DEF)=144*0.125=18
(2) Construct the triangle ABC geometrically using compass, protractor, and a ruler. Draw a line segment AB of length 12. Using the compass draw a (Thales') semi-circle centered at the midpoint of AB with radius of 6. Then, using the protractor, draw a line at 75 degrees going from point B. The intersection with the semicircle will give you point C. Finally. draw a line from C to A, completing the triangle. Then, using ruler, measure the length BC and AC.
Calculate the area(ABC)=BC*CA/2, which should come out close to 18, if you drew precisely enough.
Question:
The question is incomplete. The display technology was not given. Find below the complete question and the answers.
Display from technology:
Hypothesis Test Results
μ : Mean of variable
H₀ : μ=2.7 miles
HA : μ >2.7 miles
Variable Sample Mean Std. Err. DF T-Stat P-value
Length 3.23601 0.285185 499 2.230166 0.0131
Step-by-step explanation:
From the result obtained, we have;
Null hypothesis: H₀ : μ=2.7 miles
Alternative hypothesis: HA : μ >2.7 miles
Test statistics = 2.230166
P-value = 0.0131
Significant level: α = 0.05
Since the P value is less than the significance level, we can reject the null hypothesis.
There is no sufficient evidence to support the claim that the mean tornado length is greater than 2.7 miles
Can you send pic of graph
Step-by-step explanation:
Pls
Answer:
The price that maximizes the revenue is $20
Step-by-step explanation:
(a) Express the daily revenue from ticket sales, R as a function of the number of $1.00 price increases,
R(x) = (70000-2500x)(12+x)
(b) What ticket price maximizes the revenue from ticket sales?
The ticket price that maximizes the revenue is associated with the x of the vertex of the parabola.
R(x) = (70000-2500x)(12+x) = 840000 + 70000x - 30000x - 2500x² =
-2500x² + 40000x + 840000
x vertex = -b/2a = -40000/2.(-2500) = 8
12+8 = 20