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julsineya [31]
2 years ago
6

A cell phone company is looking to place a new tower to service 3 cities. In order for it to best service each city, it needs to

be equidistant from all 3 cities. What mathematical concept could they use to find a location that is equidistant from all 3 cities? Why is this a good method?
Mathematics
1 answer:
omeli [17]2 years ago
7 0

Answer:

  • circumscribed circle
  • The center of a circle circumscribing the triangle connecting the 3 cities will be equidistant from all three cities.

Step-by-step explanation:

The circumscribed circle or <em>circumcircle</em> of a polygon is a circle that passes through all the vertices of the polygon. The center of the circle, the circumcenter, is equidistant from all of the polygon's vertices.

The center is found at the point of intersection between the perpendicular bisectors of any two (non-parallel) chords of the circle. That is, <em>the perpendicular bisectors of any two of the sides of the triangle joining the cities will intersect at the circumcenter</em>.

The method of locating the center of the circle this way is simple and effective.

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Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
Pachacha [2.7K]

Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem

Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?

For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{1.1}

Z = 1.64

Z = 1.64 has a pvalue of 0.9495.

This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.

For the average of the sample

What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?

Now, we need to find the standard deviation of the sample before using the zscore formula. That is:

s = \frac{\sigma}{\sqrt{110}} = 0.1.

Now

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{0.1}

Z = 18

Z = 18 has a pvalue of 0.9999.

This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

7 0
2 years ago
Macy plans to buy a TV during the Black Friday Sale. All TV's are advertised as 25% off of the original price, before tax. Which
snow_lady [41]
A because p+ 0.25p is the right answer
3 0
2 years ago
Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to


m=\frac{y2-y1}{x2-x1}


we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point B(5,2)\ C(7,-5)

Find the slope BC

Substitute the values in the formula

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


so

The equation y=-3.5x-15 is parallel to the line passing through the points B(5,2)\ C(7,-5)

therefore

<u>the answer Part A) is</u>

B(5,2)\ C(7,-5) ------> y=-3.5x-15

<u>Case B)</u> Point D(11,6)\ E(5,9)

Find the slope DE

Substitute the values in the formula

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


so

The equation y=-0.5x-3 is parallel to the line passing through the points D(11,6)\ E(5,9)

therefore

<u>the answer Part B) is</u>

D(11,6)\ E(5,9) ------> y=-0.5x-3

<u>Case C)</u> Point F(-7,12)\ G(3,-8)

Find the slope FG

Substitute the values in the formula

m=\frac{-8-12}{3+7}  

m=\frac{-20}{10}


m=-2


so

Any linear equation with slope m=-2 will be parallel to the line passing through the points F(-7,12)\ G(3,-8)

<u>Case D)</u> Point H(4,4)\ I(8,9)

Find the slope HI

Substitute the values in the formula

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


so

The equation y=1.25x+4 is parallel to the line passing through the points H(4,4)\ I(8,9)

therefore

<u>the answer Part D) is</u>

H(4,4)\ I(8,9) ------> y=1.25x+4

<u>Case E)</u> Point J(7,2)\ K(-9,8)

Find the slope JK

Substitute the values in the formula

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


so

Any linear equation with slope m=-0.375 will be parallel to the line passing through the points  J(7,2)\ K(-9,8)

<u>Case F)</u> Point L(5,-7)\ M(4,-12)

Find the slope LM

Substitute the values in the formula

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


so

The equation y=5x+19 is parallel to the line passing through the points L(5,-7)\ M(4,-12)

therefore

<u>the answer Part F) is</u>

L(5,-7)\ M(4,-12) ------>  y=5x+19




8 0
2 years ago
Read 2 more answers
At the Hardey Fitness Center, the management did a survey of their membership. The average age of the female members was 40 year
faust18 [17]

Answer:

5 / 8

Step-by-step explanation:

Given :

Average age of male = 25

Average age of female = 40

Average age of entire membership = 30

The ratio of female to male students :

Male students : Female students

25 : 40

5 : 8

5/8

8 0
2 years ago
Point F is on circle C.
Mama L [17]

the answer is 17.5 units

3 0
2 years ago
Read 2 more answers
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