It appears that you have overlooked the set of options for
this problem. To solve the problem, Lynn Drew ought to use the operation of
ADDITION to find the unknown number. Given that there are 90 flowers and 54
flowers, the unknown number that you are looking for would be 144.
Equation::
value + value = value
80x + 60(50-x) = 74*50
----
80x + 60*50 - 60x = 74*50
----
20x = 14*50
x = 35 lbs (amt. of 80 cent tea to use)
50-x = 15 lbs (amt. of 60 cent tean to use)
Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}
Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid
For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36
Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30
For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22
Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98
The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32
Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
Answer:
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is 202500 swordfishes.
Step-by-step explanation:
Let be
, the maximum sustainable yield can be found by using first and second derivatives of the given function: (First and Second Derivative Tests)
First Derivative Test

Let equalize the resulting expression to zero and solve afterwards:


Second Derivative Test

This means that result on previous part leads to an absolute maximum.
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is:


The maximum sustainable yield is 202500 swordfishes.
The answer is C, a perpedicular bisector. The distances of the mark along the given line are equidistance. Where the x is located, where the two dashes would intersect is where a 90 degre angle to the line would pass through.