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marin [14]
2 years ago
5

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. limit interval lim

||δ|| → 0 n 5 ci4 i = 1 δxi [5, 9]
Mathematics
1 answer:
tankabanditka [31]2 years ago
7 0

Seems like it would be

\displaystyle\int_5^9x^4\,\mathrm dx

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A box of shredded wheat wheat weighs 0.35 .kg and a box of weetabix weighs 9/25 kg. Which box is heavier? Show your work.
MAXImum [283]

Answer:

weetablx is heavier

Step-by-step explanation:

lets simplify

wheat wheat - 0.35 kg

weetablx - 9/25

simplify into decimals

wheat wheat- 0.35 kg

weetablx- 0.36 kg

brainliest appreciated!

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2 years ago
A class trip to a ski resort has been planned for your senior trip. The mountain only allows skiing when the temperature is betw
Lelu [443]

Answer:

−10 < x < 35 and 0 < y ≤ 38

Step-by-step explanation:

8 0
2 years ago
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The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except –3. Which
Dmitrij [34]

Answer: All the real values except x ≠ 7 and the x for which f(x)≠-3

Step-by-step explanation:

Since, For function f , the domain is R - {7}

That is, If x is any element of the domain of the function f,

Then,  x ≠ 7

(gof)(x) = g(f(x))

Since, For the function g, the domain is R - {-3}

Thus,  If f(x) is any element of the domain of the function g,

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Hence, Fourth Option is correct.

8 0
2 years ago
Freshmen and Sophomores Solve by setting up a system of linear equations with 2 variables and 2 unknowns. A total of 1,595 first
VMariaS [17]

Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595   (1)
s + 15 = r      (2)

Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595  Combine like terms
2s + 15 = 1595      Subtract 15 from both sides
2s = 1595 - 15    
2s = 1580              Divide by 2
s = 1580/2
s = 795 sophmores.

s + r = 1595
795 + r = 1595     Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen

Answer C <<<<<<
8 0
2 years ago
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Students at a high school were polled to determine the type of music they preferred. There were 1940 students who
Reika [66]

Answer:

students preferred alternative music

= 461/1940 ×100%=23.7%

6 0
2 years ago
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