Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles
<em><u>Solution:</u></em>
Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip
He flew 2,567 miles from California to Hawaii during the second part of his trip
Therefore,
first part of his trip = 3547 miles
second part of his trip = 2567 miles
Difference in the number of miles Nathan flew between the first and second parts of his trip is given as:
difference = first part of his trip - second part of his trip
difference = 3547 - 2567 = 980
Therefore, the difference in number is 980 miles
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Answer:
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
Total outcomes:
100 customers
Desired outcomes:
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.
Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Answer:
1. x=±4
2. t=±9
3. r=±10
4. x=±12
5. s=±5
Step-by-step explanation:
1. x^2 = 16
Taking square root on both sides

x=±4
2. t^2=81
Taking square root on both sides

t=±9
3. r^2-100=0

r=±10
4. x²-144=0
x²=144
Taking square root on both sides

x=±12
5. 2s²=50

s=±5 ..