In order to find the sum of the given rational expressions above, here are the steps.
Firstly, you need to find the LCM of the least common denominator.
So it would look like this:
<span>3x-1 + 3x (3x-1)(x-1) + (2x)(3x)
------ ------- = ---------------------------
2x x-1 2x(x-1)
3x^2-4x+1+6x^2
----------------------
2x(x-1)
And the final result would be this:
9x^2-4x+1
--------------
2x(x-1)
</span>9x^2-4x+1
--------------
2x^2-2x
<span>
Hope that this is the answer that you are looking for.
</span>
Part A: [<span>P + (A + G) - M
</span>Part B: [0.75 + (0.25 + 0.30) - 0.20] = 1.1
Answer:
x-intercepts: (1,0), (2,0), (5,0)
y-intercepts: (0,-10)
Step-by-step explanation:
One factor of the function 
is 
Factor the polynomial in the following way:
Now factor the quadratic in brackets:
Hence,
The x-intercepts are points at which y = 0, so
The y-intercepts are points at which x = 0, so
Answer:
a) Calculate the probability that at least one of them suffers from arachnophobia.
x = number of students suffering from arachnophobia
= P(x ≥ 1)
= 1 - P(x = 0)
= 1 - [0.05⁰ x (1 - 0.05)¹¹⁻⁰
]
= 1 - (0.95)¹¹
= 0.4311999 = 0.4312
b) Calculate the probability that exactly 2 of them suffer from arachnophobia? 0.08666
= P(x = 2)
= (¹¹₂) x (0.05)² x (0.95)⁹
where ¹¹₂ = 11! / (2!9!) = (11 x 10) / (2 x 1) = 55
= 55 x 0.0025 x 0.630249409 = 0.086659293 = 0.0867
c) Calculate the probability that at most 1 of them suffers from arachnophobia?
P(x ≤ 1)
= P(x = 0) + P(x = 1)
= [(¹¹₀) x 0.05⁰ x 0.95¹¹] + [(¹¹₁) x 0.05¹ x 0.95¹⁰]
= (1 x 1 x 0.5688) + (11 x 0.05 x 0.598736939) = 0.5688 + 0.3293 = 0.8981
