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STatiana [176]
2 years ago
10

Which expression is equivalent to 7a2b + 10a2b2 + 14a2b3?

Mathematics
2 answers:
Ugo [173]2 years ago
4 0
The given expression can be simplified in many ways by grouping like terms. The simplest form is obtained by factoring out a²b which gives us the following expression.

a²b(7 + 10b +14b²)
igomit [66]2 years ago
4 0

Answer:

a^2b(7 + 10b + 14b^2)

Step-by-step explanation:

Given : 7a^2b + 10a^2b^2 + 14a^2b^3

To Find: Which expression is equivalent to 7a^2b + 10a^2b^2 + 14a^2b^3

Solution:

7a^2b + 10a^2b^2 + 14a^2b^3

Take a^2 as common

a^2(7b + 10b^2 + 14b^3)

Now take b as common

a^2b(7 + 10b + 14b^2)

Hence a^2b(7 + 10b + 14b^2) is  equivalent to 7a^2b + 10a^2b^2 + 14a^2b^3

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Answer:  

Here, The price of one box having N markers = Price of N markers + packaging charge

Let M be the price of one Marker and P' be the price of packaging of one box which is same for any size.

Since, The price of a box of 15 cloud markers is $12.70.

That is , 15 M + P' = 12.70 ---------(1)

Also,  The price of a box of 42 cloud markers is $31.60,

That is, 42 M + P' = 31.60 ---------(2),

Equation (2) - Equation (1),

27 M = 18.90,

⇒ M = 0.7

By putting the value of P in equation (1),

We get,

10.5 + P' = 12.70 ⇒ P' = 2.2,

Thus, the price of one marker, M = 0.7

And, the price of packaging one box, P' = 2.2

Thus, the price of a box of 50 marker = 50 × M + P' = 50×0.7 + 2.2 = 35 + 2.2 = $ 37.2

And, the equation that shows the price(P) of a box of N markers,

P = 0.7 N + 2.2

3 0
2 years ago
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Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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A STORE IS GIVING AWAY A $10 COUPON TO EVERY 7TH PERSON TO ENTER THE STORE AND A $25 COUPLON TO EVERY 18TH PERSON TO ENTER THE S
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2 years ago
The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca
dem82 [27]

Answer:

\frac{4}{663}

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

A - the first card is 4

B - second card is ace

We have to find probability for

A\bigcap B

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P(B) = no of Aces in 51 cards/51 = \frac{4}{51}

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