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gulaghasi [49]
2 years ago
14

Type the correct answer in each box. Round your answers to the nearest integer.

Mathematics
2 answers:
QveST [7]2 years ago
5 0
Did you ever find the awnser

Over [174]2 years ago
3 0

Answer:

(1) 92.92 unit  (2) 500 unit²

Step-by-step explanation:

(1) Perimeter of the given hexagon ABCDEF will be

   = Sum of length of all sides

   = AB + BC + CD + DE + EF + FA

   =10+(\sqrt{10^{2}+10^{2}})+\sqrt{10^{2}+10^{2}}+10+\sqrt{20^{2}+10^{2}}+\sqrt{20^{2} +10^{2} }

   = 20+10\sqrt{2} +10\sqrt{2}+10+10\sqrt{(2+1)}+10\sqrt{(2+1)}

   = (30+20\sqrt{2}+20\sqrt{3})

   = 30 + 28.28 + 34.64

   = 92.92 unit

(2) Area of hexagon = Area of ΔAEF + Area of rectangle ABDE + Area of ΔBCD

   = \frac{1}{2} (20)(20)+(20)(10)+\frac{1}{2}(20)(10)

   = 200 + 200 + 100

   = 500 unit²

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P(6) = 0.6217

Step-by-step explanation:

To find P(6), which is the probability of getting a 6 or less, we will need to first calculate two things: the mean of the sample (also known as the "expected value") and the standard deviation of the sample.  

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Standard Deviation =\sqrt{npq} = \sqrt{(18)(0.3)(0.7)}  

                                                            = 1.944

Now calculate the Z score for 6 successes.  

Z = ( of successes we're interested in - Mean) ÷ (Standard Deviation)

=(6-5.4)  ÷ (1.944) = 0.309

we have our Z-score, we look on the normal distribution and find the area of the curve to the left of a Z value of 0.309.  This is basically adding up all of the possibilities for getting less than or equal to 6 successes.  So, we get 0.6217.

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2 years ago
Sarah and thomas are going bowling. the probability that sarah scores more than 175 is 0.4, and the probability that thomas scor
pychu [463]

When the occurrence of one event say A does not affect the occurrence of another event say B, than the two events are said to be independent such that;

\\  
P(A\cap B)=P(A)\times P(B)

where, P(A) = probability of occurrence of event A

and P(B) = probability of occurrence of event B

(a).

Now, let event A = Sarah scores more than 175

and event B = Thomas scores more than 175

Thus, P(A)= Probability that Sarah scores more than 175 = 0.4

and P(B)= Probability that Thomas scores more than 175 = 0.2

Since, the scores are independent, thus the probability that both Sarah and Thomas scores more than 175 is,

\\  
P(A\cap B)=P(A)\times P(B)\\  
P(A\cap B)= 0.4\times 0.2= 0.08\\

Hence, the required probability is 0.08

(b).

When the occurrence of one event say A affects the occurrence of another event say B, than the two events are said to be dependent such that;

\\  
P(A\cap B)=P(A)\times P(B\setminus A)\\

Now, let event A = Sarah scores more than 175

and event B = Thomas scores more than 175

Thus, P(A)= Probability that Sarah scores more than 175 = 0.4

         P(B)= Probability that Thomas scores more than 175 = 0.2

and P(B|A) = Sarah scores more than Thomas given that Thomas scores more than 175 = 0.3

Thus, the required probability is calculated as follows;

\\  
P(A\cap B)=P(A)\times P(B\setminus A)\\  
P(A\cap B)=0.2\times 0.3=0.06



             



             


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