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svetlana [45]
2 years ago
6

Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a

resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total resistance in the circuit, t, with this equation, in which r represents the resistance of the second lightbulb. t = 120 ⁢ r r + 120 Find the inverse of Janine’s equation. Big fraction Parentheses Vertical bars Square root Root Superscript (Ctrl+Up) Subscript (Ctrl+Down) Plus sign Minus sign Middle dot Multiplication sign Equals sign Less-than sign Greater-than sign Less-than or equal to Greater-than or equal to Pi Alpha Beta Epsilon Theta Lambda Mu Rho Phi Sine Cosine Tangent Arcsine Arccosine Arctangent Cosecant Secant Cotangent Logarithm Logarithm to base n Natural logarithm Bar accent Right left arrow with under script Right arrow with under script Angle Triangle Parallel to Perpendicular Approximately equal to Tilde operator Degree sign Intersection Union Summation with under and over scripts Matrix with square brackets
Mathematics
2 answers:
Margaret [11]2 years ago
6 0

Answer:

-0.5 would be the most likely outcome

Step-by-step explanation:

Hope this helped<3

Sergeeva-Olga [200]2 years ago
6 0
-0.5 I believe is the correct answer
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What is the value of x in the equation below? –3 – (–8) – (–2) = x
Ghella [55]

Answer:

–3 – (–8) – (–2) = x

Step-by-step explanation:

–3 – (–8) – (–2) = x

Subtracting a negative is adding a positive

-3 +8+2 =x

Starting from left to right

5 +2 =x

7 =x

3 0
2 years ago
Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble
Jlenok [28]
33 in because 1056 divided by 32 is 33
hope you pass your test
3 0
2 years ago
Read 2 more answers
A ferry will safely accommodate 68 tons of passenger cars. Assume that the mean weight of a passenger car is 1.8 tons with stand
nika2105 [10]

Answer:

P (Z

Step-by-step explanation:

We want the probability that the 35 cars are loaded onto the ferry. Therefore:

Since  

μ=1.8  and  σ=0.5  we have:

P(X<35 )=P ( X−μ<35−1.8 )=P((X−μ)/σ<(35−1.8)/0.5)

Since  

(x−μ)/σ=Z and  

(35-1.8)/0.5=66.4

we have:

P (X

Use the standard normal table to conclude that:

P (Z

7 0
2 years ago
Read 2 more answers
Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
2 years ago
Read 2 more answers
A polling organization asked a nation-wide random sample of 1600 new brides (those who got married in the past 2 years) the foll
iren [92.7K]

Answer:

It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.

Step-by-step explanation:

Given that:

sample size n = 1600

sample mean \overline x = 20000

standard deviation = 5000

The objective is to choose from the given option about what most closely resembles the relevant box model.

The correct answer is:

It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.

However, if draws are made without replacement, the best estimate of the average amount for the bride will be $20,000

Similarly, the standard error for the sample mean = \dfrac{s}{\sqrt{n}}

= \dfrac{5000}{\sqrt{1600}}

= \dfrac{5000}{40}}

the standard error for the sample mean = 125

4 0
2 years ago
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