Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
X = E/W dimension
<span>y = N/S dimension </span>
<span>4x + 4x + 2y + 2y = 64 </span>
<span>8x + 4y = 64 </span>
<span>4y = 64 - 8x </span>
<span>y = 16 - 2x </span>
<span>Area = xy = x(16 - 2x) = 16x - 2x^2 </span>
<span>Maximum of y = ax^2 + bx + c is when x = -b / 2a </span>
<span>so x = -16 / -4 = 4 </span>
2 1/2 = 5/2
<span>ratio : 5/2 : 3/5 (soda to pineapple) </span>
<span>multiply by 2/5 </span>
<span>ratio : 1 : 6/25 (1 unit of soda to 6/25 units of pineapple)</span>
