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drek231 [11]
2 years ago
9

In hypothesis​ testing, does choosing between the critical value method or the​ P-value method affect your​ conclusion? Explain.

Mathematics
1 answer:
Artist 52 [7]2 years ago
8 0

Answer:​

The correct answer is No.

Choosing between the critical value method or the P-value method does not affect one's conclusion because both methods look at the probability of the test​ statistic's and its level of significance .

Given the methodology utilized by both methods, they usually arrive at the same conclusion.

Cheers!

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In △EKL, m∠K = 90º, m∠E = 25º, EK = 3 cm, KH - altitude. Find EH.
laiz [17]

Answer:

EH = 3.31

Step-by-step explanation:

We have been given a right angle triangle EKL. As KH has been given as the altitude (perpendicular) of the right angled triangle, and K is the right angle, we can say that EK is tthe base of the triangle and EH is the only side lleft, which is the hypotenuse of the triangle.

Where,

EK = Base = 3

KH = perpendicular altitude

EH = Hypotenuse

m<K = 90

m<E = 25

We know that

cosθ = Base/ Hypotenuse

cos 25 = 3/ EH

EH = 3/cos25

EH = 3.31

Perpendicular alitutude can also be calculated by using the formula for tanθ.

3 0
2 years ago
The owner of a garden center pays $12 for each birdbath. She sells them for 55% more than she paid. Decide whether each expressi
Verdich [7]

Answer:

1 no

2 no

3 no

4 yes

5 no

Step-by-step explanation:

4 0
2 years ago
A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column
Helen [10]

Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

1)

                         X            Y          XY       X²

                         27            13           351          729

                         65             12          780         4225

                         83              11          913         6889

                         109            10          1090      11881

                         142            9            1278     20164

                         175              8           1400      30625

                ∑      601              63 5812 74513

From y = ax + b, we have

a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x  \right )^{2}} = \frac{6 \times 5812  - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

2)

r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x  \right )^{2}] [n\sum y^{2}-\left (\sum y  \right )^{2}]}}  = \frac{6 \times 5812  - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6  \times 3969 - 63^2]} } = - 0.0725

3) The strength is - association.

5 0
2 years ago
Read 2 more answers
Students at a high school were polled to determine the type of music they preferred. There were 1940 students who
Reika [66]

Answer:

students preferred alternative music

= 461/1940 ×100%=23.7%

6 0
2 years ago
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c O
Bas_tet [7]

Answer:

  1. addition property of equality
  2. integers are closed to addition
  3. identity element
  4. multiplication property of equality
  5. commutative property of multiplication; reals are closed to multiplication; identity element

Step-by-step explanation:

<u>Given</u>:

  c/2 -5 = 7

  Step 1: c/2 -5 +5 = 7 +5

  Step 2: c/2 +0 = 12

  Step 3: c/2 = 12

  Step 4: 2(c/2) = 12(2)

  Step 5: c = 24

<u>Find</u>:

  The property that justifies each step of the solution.

<u>Solution</u>:

  Step 1: addition property of equality (lets you add the same to both sides)

  Step 2: integers are closed to addition

  Step 3: identity property of addition (adding 0 changes nothing)

  Step 4: multiplication property of equality

  Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality.  Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

8 0
2 years ago
Read 2 more answers
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