Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
,Okay, so here is how to calculate the amount of the trade discount:
I: $149,500 * .10 (10%) = 14,950 (this is the 10% discount)
149,500 - 14,950 = 134,550 (how much it costs with a 10% discount)
II: 134,550 * .5 (5%) = 6727.50
134,550 - 6727.50 = 127,822.50
III: 127,822.50 * .4 (4%) = 5112.90
The amount of the trade discount is: $14,950 + $6727.50 + $5112.90 = 26,790.40 dollars.
Answer:
No
Step-by-step explanation:
0.26*16 + 12.25 = 16.41
16.41 < 16.50
