Solve this equation zma=a+b ;for a

1 answer:

mina [271]2 years ago

5 0

Subtract b and then a = (zma) - b

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SVEN [57.7K]

Answer:

$\dfrac{\sqrt[5]{810x^3}}{3x}$

Step-by-step explanation:

As a rule, the "simplified form" means there are no fractions under a radical.

$\sqrt[5]{\dfrac{10x}{3x^3}}=\sqrt[5]{\dfrac{10x(3^4x^2)}{3x^3(3^4x^2)}}=\sqrt[5]{\dfrac{810x^3}{(3x)^5}}=\boxed{\dfrac{\sqrt[5]{810x^3}}{3x}}$

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