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r-ruslan [8.4K]
1 year ago
14

Suppose 123 people voted for Danny. If 55 of the votes were from girls, what would be the ratio of votes from girls to votes fro

m boys? Explain.
Mathematics
2 answers:
serious [3.7K]1 year ago
6 0
It would be 55:68, since there are 55 girls to the 68 boys.
Lubov Fominskaja [6]1 year ago
5 0
First, 123 - 55 = 68  which is how many boys voted. So, the ratio is 55:68
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Elsie bought a video game for $85.00. If the store charges 170% of its cost for the game, how much is the store’s profit?
MissTica

Answer: $144.50

Step-by-step explanation:

is/of = %/100

x/85 = 170/100

14,450 = 100x

divide by 100

x = $144.50

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2 years ago
The cost of phone is reduced by 30% new cost is 116.83 what was the original price of the phone
slava [35]

Answer:

p = $116.83/0.70 = $166.90

Step-by-step explanation:

let p represent the original price.  Then:

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0.70p = $116.83.

Finally,

p = $116.83/0.70 = $166.90

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strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

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then for

P(Y≥ μ+3*σ ) ≥ 0.90

5 0
2 years ago
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