Solve equation for b. H=m+1/5rb

Jim is building a rectangular deck and wants the length to be 1 ft greater than the width. what will be the dimensions of the de

Travka [436]

Let x = width
x+1 is then the length

2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)

3 0

1 year ago

the cost of an annual tuition at a university increased from 10,500 to 11,300 what is the percent increase in tuition to the nea

Maurinko [17]

Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%

rond 7.61% to tenth or to 7.6%

7.6%

5 0

2 years ago

Kira looked through online census information to determine the average number of people living in the homes in her city. What is

Goshia [24]

First we need to identify if the data is qualitative or quantitative.

The data is average number of people living in the homes.

Qualitative data as its name indicates is an attribute or characteristic. It can not be measured e.g color. Quantitative data is such a data which can be counted or measured.

Since the average number of people can be counted and measured, the data is Quantitative.

In an observational study the individuals are observed. In the given case, Kira did not observed the individuals to gather the data, rather she used an Online resource to gather the data.

Therefore, the correct answer will be:
Kira used published data that is quantitative.

4 0

2 years ago

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25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct

soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of $2\pi$ and a vertical compression.

Step-by-step explanation:

We are given the parent function as $y= \cot x$

It is given that, transformations are applied to the parent function in order to obtain the function $y=0.5\cot (0.5x)$ i.e. $y=\frac{1}{2}\cot (\frac{x}{2})$

That is, we see that,

The parent function $y= \cot x$ is stretched horizontally by the factor of $\frac{1}{2}$ which gives the function $y=\cot (\frac{x}{2})$ .

Further, the function is compressed vertically by the factor of $\frac{1}{2}$ which gives the function $y=\frac{1}{2}\cot (\frac{x}{2})$ .

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Since, the period of $y= \cot x$ is $\pi$ , so the period of $y=\frac{1}{2}\cot (\frac{x}{2})$ is $\frac{\pi}{1/2}$ = $2\pi$

Hence, we get option C is correct.

3 0

2 years ago

Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two dis

Sati [7]

Answer: The answer is f(x) = (x-3)²-h = (x-3-√h)(x-3+√h).

Step-by-step explanation: We are given to write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two distinct roots.

A quadratic function with vertex having x-coordinate k takes the form of a parabola as follows:

$f(x)+h=(x-k)^2.$

Here, 'k' and 'h' are both real.

Since we the the x-coordinate of the vertex as 3, so k = 3.

Therefore, the quadratic function becomes

$f(x)+h=(x-k)^2\\\\\Rightarrow f(x)=(x-k)^2-h\\\\\Rightarrow f(x)=(x-3-\sqrt h)(x-3+\sqrt h).$

This is the required factored form of the quadratic function.

See the attached graph, where the x-coordinate of the vertex is 3 and h is taken to be 2 units.

3 0

1 year ago

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