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Rashid [163]
2 years ago
5

If f(x) =[x] −2 + 8, what is f(−1.8)? 4 6 10 12

Mathematics
2 answers:
Agata [3.3K]2 years ago
8 0
F(x) = [x] - 2 + 8
[x] is the notation for 'greatest integer function'
f(-1.8) = [-1.8] - 2 + 8 = -2 -2 + 8 = 4
The answer is 4
Westkost [7]2 years ago
8 0

Answer:

The answer is 4

Step-by-step explanation:

I just took the test

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Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Sever21 [200]
Taking the 3 solutions as 3 different terms, we can create an equation as follows:

Solution 1 : 10mL with 20% acid
Solution 2 : 30mL with x% acid
Solution 3 : 40mL with 32% acid

Since solution 1 + solution 2 = solution 3, let us substitute the given values we have:

10(0.2) + 30(x) = 40(0.32)
2 + 30x = 12.8

To solve for the unknown concentration x, we subtract 2 from both sides:
2 + 30x - 2 = 12.8 - 2
30x = 10.8

Dividing both sides by 30:
30x/30 = 10.8/30
x = 0.36

Therefore the unknown solution is 36% acid.
4 0
1 year ago
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Jade farm has 9 chickens,each of which laid 3 eggs. Jases farm has 4 horses. ednas farm has chickens which laid a total of 23 eg
Tomtit [17]

The answer is that Jade's chickens laid more eggs. Since Jade's farm includes 9 chickens, which each laid 3 eggs, multiply 9 and 3 and you get 27. Edna's farm has chickens which, in total, laid 23 eggs, leading to Jade's chickens with 27 eggs to be more than the eggs laid by Edna's chickens. :)

6 0
2 years ago
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Consider this claim: Changes in environmental conditions always result in new ecosystems and loss of biodiversity characterized
Dafna11 [192]

Answer:

If a desert became flooded, some species would immeadiately go extinct, distrupting the ecosystem, biodiversity, and the food web. This flood might cause new species to enter the ecosystem as well, through means such as rafting. Other species would be forced to adapt to the new environment, leading to adaptation and possibly speciation. For a time the ecosystem would not be very stable, but after a relatively short time, 10 or 20 years, the ecosystem could stabilize itself. So my conclusion is that ecosystems are relatively fluid, they can adapt to almost anything if they have enough time and the change in environment isn’t too drastic.

Step-by-step explanation:

4 0
2 years ago
Which option lists an expression that is not equivalent to 4 2/3?
I am Lyosha [343]

Answer:

Option A and Option B are not equivalent to the given expression.

Step-by-step explanation:

We are given the following expression:

4^{\frac{2}{3}}

Applying properties of exponents and base:

(a^x)^y = a^{xy}\\a^{-x}= (\frac{1}{a})^x\\

A. Using the exponential property a^{-x}= (\frac{1}{a})^x\\, we can write:

0.25^{\frac{3}{2}} = (\frac{1}{0.25})^{\frac{-3}{2}} = (4)^{\frac{-3}{2}}

which is not equal to the given expression.

B. Using the exponential property a^{-x}= (\frac{1}{a})^x\\, we can write:

(0.25)^{\frac{-3}{2}} = (\frac{1}{0.25})^{\frac{3}{2}} = (4)^{\frac{3}{2}}

which is not equal to the given expression.

C. First we convert the radical form into exponent form. Then by using the property (a^x)^y = a^{xy} of exponent, we can write the following:

^3\sqrt{16} = (16)^{\frac{1}{3}} = (4^2)^{\frac{1}{3}} = 4^{\frac{2}{3}}

which is equal to the given expression.

D. First we convert the radical form into exponent form. Then by using the property (a^x)^y = a^{xy} of exponent, we can write the following:

(^3\sqrt{4})^2 = (4^{\frac{1}{3}})^2 = 4^{\frac{2}{3}}

which is equal to the given expression.

Option D and Option C are equivalent to the given expression.

7 0
2 years ago
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If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?
lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

C = 9 * 10^2kg

C = 9 *100kg

C = 900kg

B = 1.8 * 10^5kg

B = 1.8 * 100000kg

B = 180000kg

Divide the bigger weight by the smaller weight

\frac{B}{C} = \frac{180000kg}{900kg}

\frac{B}{C} = \frac{180000}{900}

\frac{B}{C} = {200}{}

Multiply both sides by C

C * \frac{B}{C} = {200}{} * C

B = {200}{} * C

B = 200}C

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

7 0
1 year ago
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