Sixty-five campers arrive. Nine go home early. If 8 people sleep in 1 tent, how many tents will the campers need?

Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve

saw5 [17]

The correct answer for this problem is a. $39695. Hope this helps!

7 0

2 years ago

Read 2 more answers

"Our customer retention rate has decreased 10% from last quarter's goal of 250 consumers retained. We need to increase our curre

Lorico [155]

1. multiply 250 by 10% (250 * .1= 25)
2. Then subtract 25 from 250 (250 -25= 225)
2. Then multiply 225 by 16% (225 * .16 = 36)
3. Add 225 + 36 = 261.
4. 261 is your final answer

6 0

2 years ago

A Gardener has 2 tulip bulb, 45 tomato plants, 108 rose bushes, and 126 herd seedling to plant in the city garden. He want each

NNADVOKAT [17]

Answer: <em> $9\ rows$ </em>

Step-by-step explanation:

<h3> <em>The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />

The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.

You can follow these steps in order to find the GCF:

1. You must decompose 27, 45, 108 and 126into their prime factors:

$27=3*3*3=3^3\\\\45=3*3*5=3^2*5\\\\108=2*2*3*3*3=2^2*3^3\\\\126=2*3*3*7=2*3^2*7$

2. You must multiply the commons with the lowest exponents. Then:

Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:

$9\ rows$

3 0

2 years ago

It is claimed that 55% of marriages in the state of California end in divorce within the first 15 years. A large study was start

kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that $p = 0.55$

Suppose 10 marriages are randomly selected.

This means that $n = 10$

What is the probability that less than two of them ended in a divorce?

This is

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045$

0.0045 = 0.45% probability that less than two of them ended in a divorce

8 0

1 year ago

a jewelry is designing a crown. the crown must have at least 45 gems using only emeralds, rubies, and diamonds. the number of ru

stepladder [879]

I'm horrible at this so I'm just guessing.
X is the variable and x means multiplication symbol.
X + (X x 3 - 1) + (X x 3 - 1) - 4) <span>≥ 45 is the answer I got.
The answer to that inequality would be
X </span><span>≥ 7 I think.</span>

5 0

2 years ago