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finlep [7]
2 years ago
10

What is the volume of the pyramid?

Mathematics
2 answers:
s2008m [1.1K]2 years ago
5 0

Answer:

16\sqrt{3} cm^{3}

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo,

<em>A solid oblique pyramid has an equilateral triangle as a base with an edge length of 4StartRoot 3 EndRoot cm and an area of 12StartRoot 3 EndRoot cm2. </em>

<em>What is the volume of the pyramid?</em>

My answer:

As we know, The volume of a pyramid = \frac{1}{3}base area × its height

Given:

  • Side lenght of the base is; 4\sqrt{3} cm

=> The area of the base is 12\sqrt{3} cm^{2}

  • In Δ ACB measure of angle ACB is 90° and m∠ CAB is 30°

We use: tan(30) = \frac{BC}{AC}

<=> BC = 4\sqrt{3}*tan(30)

= 4 cm

And BC is the height of the the pyramid

=> The volume of a pyramid = \frac{1}{3} 12\sqrt{3} cm^{2} * 4 cm

= 16\sqrt{3} cm^{3}

SOVA2 [1]2 years ago
5 0

Answer:

B

Step-by-step explanation:

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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
1 year ago
What percent of 137.4 is 96?
Neporo4naja [7]
X = 96

100 137.4

137.4x=(100)(96)

137.4x=9600

137.4x/137.4=9600/137.4

x=70%
7 0
2 years ago
Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l
lbvjy [14]
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
7 0
2 years ago
Read 2 more answers
In a sale normal prices are reduced by 10% Nathalie bought pair of shoes in the sale for ?54 what was the original price
Mama L [17]

Answer:

$59.4

Step-by-step explanation:

7 0
2 years ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
FrozenT [24]

Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

Step-by-step explanation:

Let ABCD is the trapezoid, ( shown in below diagram)

In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7

Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

⇒ \frac{3+x}{18} = \frac{x}{11}

⇒  33 +11x = 18x

⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

But, AP= PD + DA

AP= 4\frac{5}{7}+3 =7\frac{5}{7}

Now, let PC =y,

⇒ \frac{7+y}{18} = \frac{y}{11}

⇒ 77 + 11y = 18y

⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



7 0
1 year ago
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