Answer:
369 students have taken a course in either calculus or discrete mathematics
Step-by-step explanation:
I am going to build the Venn's diagram of these values.
I am going to say that:
A is the number of students who have taken a course in calculus.
B is the number of students who have taken a course in discrete mathematics.
We have that:

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and
is the number of students who have taken a course in both calculus and discrete mathematics.
By the same logic, we have that:

188 who have taken courses in both calculus and discrete mathematics.
This means that 
212 who have taken a course in discrete mathematics
This means that 
345 students at a college who have taken a course in calculus
This means that 
How many students have taken a course in either calculus or discrete mathematics

369 students have taken a course in either calculus or discrete mathematics
X = 96
100 137.4
137.4x=(100)(96)
137.4x=9600
137.4x/137.4=9600/137.4
x=70%
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
Answer: The length of segments between this point and the vertices of greater base are
and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,

Let, DP =x
⇒ 
⇒ 33 +11x = 18x
⇒ x = 33/7= 
Thus, PD= 
But, AP= PD + DA
AP= 
Now, let PC =y,
⇒ 
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18