Suppose that 76% of americans prefer coke to pepsi. A sample of 27 was taken. What is the probability that less than sixty perce
1 answer:
Answer:
0.0403
Step-by-step explanation:
Given that 76% of americans prefer coke to pepsi.
Let x be the number of people who prefers coke to pepsi.
X is binomial as each trial is independent, and there are only two outcomes.
A sample of 27 was taken.
We have to find the probability that less than sixty percent of the sample prefers coke to pepsi
60% of 27 =
Required probability =
Hence prob=0.0403
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